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anonymous
 one year ago
Plzz helpp! easy medal :)
Factor x2  2x + 3.
anonymous
 one year ago
Plzz helpp! easy medal :) Factor x2  2x + 3.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0A. (x  3)(x  1) B. (x + 3)(x + 1) C. (x  3)(x + 1) D. Prime

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think the answer is D  Prime

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0out of 10 how postive r u and can u explain plz why you think that @samchick1074

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Hero can you come check my answer bro?

Hero
 one year ago
Best ResponseYou've already chosen the best response.2@Calvin3, can you please explain how you arrived at D as your answer?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0as you can see up there Sam chick thinks it's D but I wasn't sure if he was right so, from the way you asked me i'm taking it that D is wrong and my answer is C am I right? @Hero

Hero
 one year ago
Best ResponseYou've already chosen the best response.2So basically, you admit that you did not use any strategy to come up with D, which means you're essentially guessing, which is okay because we've all guessed at one point or another.

Hero
 one year ago
Best ResponseYou've already chosen the best response.2But, here's a bit of information that can help you out: For a polynomial of the form \(ax^2 + bx + c\), the expression is factorable if \(b^2 = 4ac\) is a perfect square. Otherwise, it is prime.

Hero
 one year ago
Best ResponseYou've already chosen the best response.2So, basically, your first step is to figure out whether \(b^2  4ac\) is factorable first before doing anything else.

Hero
 one year ago
Best ResponseYou've already chosen the best response.2Sorry \(b^2  4ac\) not \(b^2 = 4ac\)
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