anonymous
  • anonymous
Every evening Jenna empies her pockets and puts her change in a jar. At the end of the week she counts her money. One week she had 40 coins, all of them dimes and quarters. When she added them up, she had a total of $7.75. d= number of dimes q= number of quarters How many quarters did Jenna have?
Algebra
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anonymous
  • anonymous
Every evening Jenna empies her pockets and puts her change in a jar. At the end of the week she counts her money. One week she had 40 coins, all of them dimes and quarters. When she added them up, she had a total of $7.75. d= number of dimes q= number of quarters How many quarters did Jenna have?
Algebra
schrodinger
  • schrodinger
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
d+q=40 but I don't know what to do next
anonymous
  • anonymous
\[( d + q = 40, 10 d + 25 q = 775 )\]
anonymous
  • anonymous
The second equation concerns pennies. { d -> 15, q -> 25 }

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anonymous
  • anonymous
ok so then you can substitute the values and find the answer
anonymous
  • anonymous
so 15+25=40
anonymous
  • anonymous
I got 15 dimes and 25 quarters
anonymous
  • anonymous
Replace d below with 40-q 10 d + 25 q = 775 /. d -> 40 - q solve the following for q: 10 (40 - q) + 25 q = 775
anonymous
  • anonymous
15*10+25*25=775
anonymous
  • anonymous
thank u :D

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