anonymous
  • anonymous
The figure below shows a shaded rectangular region inside a large rectangle:
Mathematics
  • Stacey Warren - Expert brainly.com
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
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anonymous
  • anonymous
What is the probability that a point chosen inside the large rectangle is not in the shaded region?
welshfella
  • welshfella
first find the area of the unshaded part = area of whole rectangle - shaded part

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welshfella
  • welshfella
can you do that?
anonymous
  • anonymous
yes
anonymous
  • anonymous
24
welshfella
  • welshfella
ok then the required probability = area unshaded / area whole rectangle - as simple as that.
anonymous
  • anonymous
ok please check my answer though..hold on :)
welshfella
  • welshfella
no 24 is the area of shaded part ( 4*6*
anonymous
  • anonymous
yes thats what i meant
welshfella
  • welshfella
so what is the area of the outer unsshaded part?
anonymous
  • anonymous
50?
welshfella
  • welshfella
No thats the area of the whole triangle - the shaded + unshaded
anonymous
  • anonymous
so its 30 right? for the unshaded part
welshfella
  • welshfella
|dw:1437590676443:dw|
welshfella
  • welshfella
(5*10) - (6*4) = 50 - 24 = ?
anonymous
  • anonymous
26
welshfella
  • welshfella
right so what is the probability of the point being in the outer unshaded part?
anonymous
  • anonymous
26%
welshfella
  • welshfella
no check my third post
anonymous
  • anonymous
ok so im confused...what do i do then with 26?
welshfella
  • welshfella
probability = area of unshaded part / area of the whole recatngle this will give you a fraction to get a percent you multiply it by 100.
welshfella
  • welshfella
area unshaded = 26 , area of whole = 50
welshfella
  • welshfella
probability = area of unshaded / area of whole = 26/50
anonymous
  • anonymous
i got 0.52, sry my mom was calling me lol :b @welshfella
anonymous
  • anonymous
so its 52% right?
welshfella
  • welshfella
yes
anonymous
  • anonymous
ok thank you!!!

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