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Photon336
 one year ago
Chem problem
Will post it in a bit.
Photon336
 one year ago
Chem problem Will post it in a bit.

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Photon336
 one year ago
Best ResponseYou've already chosen the best response.0Thought it was a good idea to post this. it's kind of tricky

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do you include the solids in the Keq? why?

Photon336
 one year ago
Best ResponseYou've already chosen the best response.0@Cuanchi \[K _{eq} = \frac{ [C]^x[D]^y }{ [A]^c[B]^d }\] they don't give us any information about the Keq, but i totally misread it, like i figure that solids wont be included in that but the explanation was "their concentarations don't change much" but isn that the same for liquids?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes pure liquids (l) and solids (s) are not included in the equilibrium constant, only gases (g) and aqueous (aq) are included.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0from which manual did you got that question?

Photon336
 one year ago
Best ResponseYou've already chosen the best response.0that has to do with how [ ] changes right?

Photon336
 one year ago
Best ResponseYou've already chosen the best response.0the books are called McGrawHill's 500 questions if you guys are interested

Photon336
 one year ago
Best ResponseYou've already chosen the best response.0i didn't even read the question and then thought oh if I add more of the solid should increase the rate.

taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.1Happens to everyone, I know I like to think liquids count for a lot more stuff than they actually do. But going back to the question so the only compound that is included is the Cl2 meaning that Keq=1/[Cl2]. I think that when Keq is greater than one there is a lot of product so the reaction wants to go left but when Keq is less than one the reaction goes to the right (I think that's right).

Photon336
 one year ago
Best ResponseYou've already chosen the best response.0There's Keq and then Kc something like that.

Photon336
 one year ago
Best ResponseYou've already chosen the best response.0Don't remember off the top of my head; i believe that it's Kq not Kc Something like when Q < K rxn goes to the right. Q>K rxn goes to left.

Photon336
 one year ago
Best ResponseYou've already chosen the best response.0So Tara SnCl2 would be considered a pure liquid? Originally I thought it was [SnCl2]/[Cl2]

taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.1Found a pretty good link for the rules for K and Q partly because I am always forgetting them http://chemwiki.ucdavis.edu/Physical_Chemistry/Equilibria/Chemical_Equilibria/The_Reaction_Quotient/Difference_Between_K_And_Q Also why pure liquid for SnCl2 I thought that was a solid?

Photon336
 one year ago
Best ResponseYou've already chosen the best response.0@taramgrant0543664 i meant to put SnCl4 in the expression. mistake lol

taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.1Haha mistakes happen to everybody!! The SnCl4 I wouldn't but it in the equation since you don't put liquids into the equation and it wouldn't count in the equilibrium since the solution has to either be aqueous or a gas
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