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anonymous

  • one year ago

I really need help and a medal will be given!

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  1. anonymous
    • one year ago
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    ok so the question is:

  2. anonymous
    • one year ago
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    ..

  3. anonymous
    • one year ago
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    how would i solve 3/5x=-1/5x+3

  4. anonymous
    • one year ago
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    \[\frac{ 3 }{ 5 }x=-\frac{ 1 }{ 5}x+3\]

  5. anonymous
    • one year ago
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    Cross multiplcation \[\huge~\rm~\frac{ 3 }{ 5x }=\frac{ -1 }{ 5x+3 }\]

  6. anonymous
    • one year ago
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    what do i do?

  7. anonymous
    • one year ago
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    multiply 5x by -1 and 3 by 5x+3?

  8. anonymous
    • one year ago
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    \(\color{#0cbb34}{\text{Originally Posted by}}\) @SpooderWoman \[\frac{ 3 }{ 5 }x=-\frac{ 1 }{ 5}x+3\] \(\color{#0cbb34}{\text{End of Quote}}\) Is this your question?

  9. anonymous
    • one year ago
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    yes

  10. anonymous
    • one year ago
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    i need to solve for x

  11. anonymous
    • one year ago
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    \[\huge~\rm~3/ 5 x+ 1 5 x= −1 /5 x+3+ 1 /5 x\] We add 1/5 to both sides

  12. anonymous
    • one year ago
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    so it would be 4/5x=3?

  13. anonymous
    • one year ago
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    yes the we multiply both sides by the reciprocal of 4/5 which is.....?

  14. anonymous
    • one year ago
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    3/1?

  15. anonymous
    • one year ago
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    No the recoprocal is just the flipped fraction it would be 5/4 now multiply both sides by that

  16. anonymous
    • one year ago
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    oh ok so it would be x=15/4?

  17. anonymous
    • one year ago
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    yep good job :)

  18. anonymous
    • one year ago
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    thank you :D

  19. anonymous
    • one year ago
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    :D

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spraguer (Moderator)
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