anonymous
  • anonymous
I will fan and medal! If θ is in Quadrant IV and sinθ = -1/2, then cosθ=? the choices are: -(2sqrt(3)/3) -(sqrt(3)/2) sqrt(3)/2 (2sqrt(3)/3)
Mathematics
chestercat
  • chestercat
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Crissy15
  • Crissy15
Nnesha
  • Nnesha
draw a right triangle in quadrant 4 |dw:1437594378716:dw| definition of sin \[\large\rm sin = \frac{ opposite }{ hypothounuse }\] cos = adjacent over hypotenuse apply Pythagorean theorem find the 3rd side of the right triangle \[\huge\rm a^2 +b^2 = c^2\]
anonymous
  • anonymous
the third side is sqrt(3) so cos=sqrt(3)/2 @Nnesha right?

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Nnesha
  • Nnesha
:=)
anonymous
  • anonymous
thanks @Nnesha
Nnesha
  • Nnesha
my pleasure :=)

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