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## anonymous one year ago I will fan and medal! If θ is in Quadrant IV and sinθ = -1/2, then cosθ=? the choices are: -(2sqrt(3)/3) -(sqrt(3)/2) sqrt(3)/2 (2sqrt(3)/3)

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1. Crissy15

@Jacob902

2. Nnesha

draw a right triangle in quadrant 4 |dw:1437594378716:dw| definition of sin $\large\rm sin = \frac{ opposite }{ hypothounuse }$ cos = adjacent over hypotenuse apply Pythagorean theorem find the 3rd side of the right triangle $\huge\rm a^2 +b^2 = c^2$

3. anonymous

the third side is sqrt(3) so cos=sqrt(3)/2 @Nnesha right?

4. Nnesha

:=)

5. anonymous

thanks @Nnesha

6. Nnesha

my pleasure :=)

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