## anonymous one year ago WILL MEDAL AND FAN how do u find the theoretical probability

1. anonymous

@ganeshie8 @pooja195 @Michele_Laino @Hero

2. anonymous

@Luigi0210

3. anonymous

@dani_00

4. anonymous

is that the whole question ??

5. anonymous

no. it my personal question

6. anonymous

to help solve a different ?

7. anonymous

? = question

8. anonymous

no im just saying b/c thats non specific question. you dont find it, its a way of thinking that can relate to possible answers, get what im saying ?

9. anonymous

sorta. but my school says this is how u find it and i dont understand $\frac{ outcomes }{ number~of~possible~outcomes }$

10. anonymous

its like weighing the options you have. idk how to explain it

11. anonymous

yes!!!

12. SolomonZelman

theoretical theory... lol...

13. anonymous

thats exactly what im trying to do. hang on

14. anonymous

15. SolomonZelman

a coin can fall on either heads or tails.... (right?) So how many possible outsomes is there?

16. anonymous

2

17. SolomonZelman

flipping the coin 100, omg, slap the teacher:O

18. anonymous

i posted in comments what i have to submit

19. anonymous

i have to flip TWO coins 100 times lol

20. anonymous

@Mehek14 :)

21. anonymous

meow

22. SolomonZelman

ok... experimental probability. Do you know what this term means?

23. anonymous

meow

24. anonymous

the number of desired outcomes divided by the total # of trials. what is a desired outcome? and the total # of trials is what? in this case

25. anonymous

correct!

26. SolomonZelman

the desired number of outcomes varies. the total number fo trials is 100

27. SolomonZelman

the I mean number of desired outcomes.

28. anonymous

~meow~

29. anonymous

but what is the desired # of outcomes in this case? IM SO CONFUSED :( !!!!!!!!!

30. anonymous

o wait no sorry

31. anonymous

32. anonymous

@emma.elizabeth5683

33. SolomonZelman

For a question: 2. What is the experimental probability that a coin toss results in two heads showing? desired outcome is when both coins lands on heads. the number of desired outcomes, is the number of times when both coins landed on heads. the total number of trials is the number times you have tossed (i.e. 100)

34. anonymous

Number of ways to succeed is one Number of possible outcomes is two Probability of getting heads is 1/2

35. anonymous

so 32 / 100 for theoretical probability?

36. SolomonZelman

number of desired outcomes / total number of trials is experimental probability

37. anonymous

i meant 32 / 3

38. anonymous

or 100 / 3?

39. anonymous

im so confused

40. anonymous

what is your exact question given to you? c:

41. SolomonZelman

so experimental probability (for question 2) is: (if you don't remember question 2, please read it) $$P=\rm (number~of~desired~outcomes)/(total~number~of~trials)$$ $$P=\rm (32)/(100)$$ $$P=\rm 0.32~~~~~or,~~8/25$$

42. anonymous

i said 32/100 first!!!

43. SolomonZelman

yes

44. anonymous

its 32% for the theoretical probability, yes?

45. SolomonZelman

and that is experimental probability for tossing both coins tails

46. SolomonZelman

i confused the info 2 tails = 28 times 2 heads = 32 times

47. anonymous

yes

48. SolomonZelman

So, for question 2 it is 32% and for question 4 it is ? (do the same thing as we did for question 2)

49. anonymous

wait...im still on ? #1

50. anonymous

whats #1?

51. SolomonZelman

u know what "theoretical probability" is?

52. anonymous

no..that was my initial question

53. anonymous

well sorta

54. anonymous

@campbell_st

55. anonymous

@Kash_TheSmartGuy

56. campbell_st

theoretical probability is what you expect to happen if you toss a coin P(head) = 1/2 and P(tail) = 1/2 its as simple as that

57. SolomonZelman

theoretical probability. We don't look at any experiments that took place before. How many outcomes does a paticular operation (for ex. tossing a coin) can have? Now, what are the chances that it will behave in a particular way? The coin example: A coin can land on either heads or tails. What is a chance that coin lands on tails? It is 1/2.... So the theoretical probability of the coin landing on tails is 1/2.

58. anonymous

so it is 33%?

59. SolomonZelman

What is the chance that both coins will land on heads? The first coin has a 1/2 (or 50%) chance of landing on heads. The second coin has a 1/2 (or 50%) chance of landing on heads as well. But these are dependent events (since you want both of these to occur, so that both coins land on heads). This means that we multiply the probabilities/chances. ½ • ½ = ¼ (or 25%)

60. SolomonZelman

Again, we aren't looking at how many times you have tossed the coins. The experiment is IRRELEVANT to any theoretical probability question that you have.

61. anonymous

im still really confused and it needs to be done by 5

62. anonymous

!!!

63. anonymous

@Elsa213 @Skielerlucas04

64. anonymous

what the question

65. Elsa213

@KyanTheDoodle is smart. Probably she can help. c:

66. anonymous

i attached it in the comments. ill attach it again though

67. anonymous

68. anonymous

im having trouble determining what a desirable outcome is

69. anonymous

@Vocaloid @Icedragon50

70. anonymous

@Skielerlucas04 plz DONT LEAVE!!!

71. anonymous

$$im~very~desperate!!!!!!!!!!!!!!!!!!!!!!!!!!!!!~$$

72. anonymous

idk how to do this, i have a LOT of work to do myself

73. anonymous

do u know what a desirable outcome is?

74. anonymous

@SolomonZelman can u help me more?

75. anonymous

ughhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

76. anonymous

@Kash_TheSmartGuy @KyanTheDoodle

77. anonymous

@nincompoop

78. anonymous

HELP!!!!!!!!!!!!!!!!!!!!!!!

79. Kash_TheSmartGuy

Ok. calm down

80. Kash_TheSmartGuy

81. Kash_TheSmartGuy

@muscrat123

82. Kash_TheSmartGuy

Suppose you have a coin and your favor is to have tails. The theoretical probability would be: $\frac{ Possible FovorableOutcomes }{ Number Of Outcomes }$So that would result in a theoretical probability of $\frac{ 1 }{ 2 }$

83. Kash_TheSmartGuy

@Jaynator495

84. anonymous

nevermind. i figured it out on my own. and it would be 33.3% , not 50% bc there are 3 possible outcomes

85. Kash_TheSmartGuy

I mentioned jay because in middle of testing.

86. KyanTheDoodle

Woah! Woah woah! I don't know how to read!

87. anonymous

? @KyanTheDoodle

88. anonymous

u dont know how 2 read?