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muscrat123

  • one year ago

WILL MEDAL AND FAN how do u find the theoretical probability

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  1. muscrat123
    • one year ago
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    @ganeshie8 @pooja195 @Michele_Laino @Hero

  2. muscrat123
    • one year ago
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    @Luigi0210

  3. muscrat123
    • one year ago
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    @dani_00

  4. anonymous
    • one year ago
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    is that the whole question ??

  5. muscrat123
    • one year ago
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    no. it my personal question

  6. muscrat123
    • one year ago
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    to help solve a different ?

  7. muscrat123
    • one year ago
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    ? = question

  8. anonymous
    • one year ago
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    no im just saying b/c thats non specific question. you dont find it, its a way of thinking that can relate to possible answers, get what im saying ?

  9. muscrat123
    • one year ago
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    sorta. but my school says this is how u find it and i dont understand \[\frac{ outcomes }{ number~of~possible~outcomes }\]

  10. anonymous
    • one year ago
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    its like weighing the options you have. idk how to explain it

  11. muscrat123
    • one year ago
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    yes!!!

  12. SolomonZelman
    • one year ago
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    theoretical theory... lol...

  13. muscrat123
    • one year ago
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    thats exactly what im trying to do. hang on

  14. muscrat123
    • one year ago
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  15. SolomonZelman
    • one year ago
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    a coin can fall on either heads or tails.... (right?) So how many possible outsomes is there?

  16. anonymous
    • one year ago
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    2

  17. SolomonZelman
    • one year ago
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    flipping the coin 100, omg, slap the teacher:O

  18. muscrat123
    • one year ago
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    i posted in comments what i have to submit

  19. muscrat123
    • one year ago
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    i have to flip TWO coins 100 times lol

  20. anonymous
    • one year ago
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    @Mehek14 :)

  21. muscrat123
    • one year ago
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    meow

  22. SolomonZelman
    • one year ago
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    ok... experimental probability. Do you know what this term means?

  23. anonymous
    • one year ago
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    meow

  24. muscrat123
    • one year ago
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    the number of desired outcomes divided by the total # of trials. what is a desired outcome? and the total # of trials is what? in this case

  25. anonymous
    • one year ago
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    correct!

  26. SolomonZelman
    • one year ago
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    the desired number of outcomes varies. the total number fo trials is 100

  27. SolomonZelman
    • one year ago
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    the I mean number of desired outcomes.

  28. anonymous
    • one year ago
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    ~meow~

  29. muscrat123
    • one year ago
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    but what is the desired # of outcomes in this case? IM SO CONFUSED :( !!!!!!!!!

  30. anonymous
    • one year ago
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    o wait no sorry

  31. anonymous
    • one year ago
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    i made a mistake sorry

  32. muscrat123
    • one year ago
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    @emma.elizabeth5683

  33. SolomonZelman
    • one year ago
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    For a question: 2. What is the experimental probability that a coin toss results in two heads showing? desired outcome is when both coins lands on heads. the number of desired outcomes, is the number of times when both coins landed on heads. the total number of trials is the number times you have tossed (i.e. 100)

  34. anonymous
    • one year ago
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    Number of ways to succeed is one Number of possible outcomes is two Probability of getting heads is 1/2

  35. muscrat123
    • one year ago
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    so 32 / 100 for theoretical probability?

  36. SolomonZelman
    • one year ago
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    number of desired outcomes / total number of trials is experimental probability

  37. muscrat123
    • one year ago
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    i meant 32 / 3

  38. muscrat123
    • one year ago
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    or 100 / 3?

  39. muscrat123
    • one year ago
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    im so confused

  40. anonymous
    • one year ago
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    what is your exact question given to you? c:

  41. SolomonZelman
    • one year ago
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    so experimental probability (for question 2) is: (if you don't remember question 2, please read it) \(P=\rm (number~of~desired~outcomes)/(total~number~of~trials)\) \(P=\rm (32)/(100)\) \(P=\rm 0.32~~~~~or,~~8/25\)

  42. muscrat123
    • one year ago
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    i said 32/100 first!!!

  43. SolomonZelman
    • one year ago
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    yes

  44. muscrat123
    • one year ago
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    its 32% for the theoretical probability, yes?

  45. SolomonZelman
    • one year ago
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    and that is experimental probability for tossing both coins tails

  46. SolomonZelman
    • one year ago
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    i confused the info 2 tails = 28 times 2 heads = 32 times

  47. muscrat123
    • one year ago
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    yes

  48. SolomonZelman
    • one year ago
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    So, for question 2 it is 32% and for question 4 it is ? (do the same thing as we did for question 2)

  49. muscrat123
    • one year ago
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    wait...im still on ? #1

  50. muscrat123
    • one year ago
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    whats #1?

  51. SolomonZelman
    • one year ago
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    u know what "theoretical probability" is?

  52. muscrat123
    • one year ago
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    no..that was my initial question

  53. muscrat123
    • one year ago
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    well sorta

  54. muscrat123
    • one year ago
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    @campbell_st

  55. muscrat123
    • one year ago
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    @Kash_TheSmartGuy

  56. campbell_st
    • one year ago
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    theoretical probability is what you expect to happen if you toss a coin P(head) = 1/2 and P(tail) = 1/2 its as simple as that

  57. SolomonZelman
    • one year ago
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    theoretical probability. We don't look at any experiments that took place before. How many outcomes does a paticular operation (for ex. tossing a coin) can have? Now, what are the chances that it will behave in a particular way? The coin example: A coin can land on either heads or tails. What is a chance that coin lands on tails? It is 1/2.... So the theoretical probability of the coin landing on tails is 1/2.

  58. muscrat123
    • one year ago
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    so it is 33%?

  59. SolomonZelman
    • one year ago
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    What is the chance that both coins will land on heads? The first coin has a 1/2 (or 50%) chance of landing on heads. The second coin has a 1/2 (or 50%) chance of landing on heads as well. But these are dependent events (since you want both of these to occur, so that both coins land on heads). This means that we multiply the probabilities/chances. ½ • ½ = ¼ (or 25%)

  60. SolomonZelman
    • one year ago
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    Again, we aren't looking at how many times you have tossed the coins. The experiment is IRRELEVANT to any theoretical probability question that you have.

  61. muscrat123
    • one year ago
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    im still really confused and it needs to be done by 5

  62. muscrat123
    • one year ago
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    !!!

  63. muscrat123
    • one year ago
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    @Elsa213 @Skielerlucas04

  64. anonymous
    • one year ago
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    what the question

  65. Elsa213
    • one year ago
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    @KyanTheDoodle is smart. Probably she can help. c:

  66. muscrat123
    • one year ago
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    i attached it in the comments. ill attach it again though

  67. muscrat123
    • one year ago
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  68. muscrat123
    • one year ago
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    im having trouble determining what a desirable outcome is

  69. muscrat123
    • one year ago
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    @Vocaloid @Icedragon50

  70. muscrat123
    • one year ago
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    @Skielerlucas04 plz DONT LEAVE!!!

  71. muscrat123
    • one year ago
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    \(im~very~desperate!!!!!!!!!!!!!!!!!!!!!!!!!!!!!~\)

  72. anonymous
    • one year ago
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    idk how to do this, i have a LOT of work to do myself

  73. muscrat123
    • one year ago
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    do u know what a desirable outcome is?

  74. muscrat123
    • one year ago
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    @SolomonZelman can u help me more?

  75. muscrat123
    • one year ago
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    ughhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

  76. muscrat123
    • one year ago
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    @Kash_TheSmartGuy @KyanTheDoodle

  77. muscrat123
    • one year ago
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    @nincompoop

  78. muscrat123
    • one year ago
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    HELP!!!!!!!!!!!!!!!!!!!!!!!

  79. Kash_TheSmartGuy
    • one year ago
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    Ok. calm down

  80. Kash_TheSmartGuy
    • one year ago
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    Let's start with an example okay?

  81. Kash_TheSmartGuy
    • one year ago
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    @muscrat123

  82. Kash_TheSmartGuy
    • one year ago
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    Suppose you have a coin and your favor is to have tails. The theoretical probability would be: \[\frac{ Possible FovorableOutcomes }{ Number Of Outcomes }\]So that would result in a theoretical probability of \[\frac{ 1 }{ 2 }\]

  83. Kash_TheSmartGuy
    • one year ago
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    @Jaynator495

  84. muscrat123
    • one year ago
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    nevermind. i figured it out on my own. and it would be 33.3% , not 50% bc there are 3 possible outcomes

  85. Kash_TheSmartGuy
    • one year ago
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    I mentioned jay because in middle of testing.

  86. KyanTheDoodle
    • one year ago
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    Woah! Woah woah! I don't know how to read!

  87. muscrat123
    • one year ago
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    ? @KyanTheDoodle

  88. muscrat123
    • one year ago
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    u dont know how 2 read?

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