anonymous
  • anonymous
1. Given h = -2 and k = 4, what is the equation of the graph if the parent function is y= square root x 2. Given h = -2 and a = -3, what is the equation of the graph if the parent function is y= square root x
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
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anonymous
  • anonymous
anonymous
  • anonymous
@surjithayer
anonymous
  • anonymous
@Kash_TheSmartGuy

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More answers

Kash_TheSmartGuy
  • Kash_TheSmartGuy
@Jaynator495
Kash_TheSmartGuy
  • Kash_TheSmartGuy
http://openstudy.com/study#/updates/54359f48e4b088157637986e Answer to no.1 Once you know how to solve it, you can solve no.2 by yourself
anonymous
  • anonymous
Ok thanks
Kash_TheSmartGuy
  • Kash_TheSmartGuy
no probs!
anonymous
  • anonymous
@KAKES1967
anonymous
  • anonymous
@Loser66
anonymous
  • anonymous
@Loser66 can you help explain the problem?
Loser66
  • Loser66
from \(y =\sqrt{x}\), we have \(x =y^2\) and the vertex is (0,0) , the graph is |dw:1437603450677:dw|
Loser66
  • Loser66
now, the vertex form is \(x =a (y-k)^2+h \) , from the given one, we have a =1, h, k are given, just plug in!!
Loser66
  • Loser66
Remember, if y = x^2 , then the vertex form is y = a(x-h)^2 +k, but this problem gives us x =y^2, hence the location of h, k on vertex form are exchanged.
anonymous
  • anonymous
Thanks @Loser66 @KAKES1967
anonymous
  • anonymous
Np (:

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