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anonymous
 one year ago
Solve 3(2x) = 7(x−1).
anonymous
 one year ago
Solve 3(2x) = 7(x−1).

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nincompoop
 one year ago
Best ResponseYou've already chosen the best response.1what do you think you should do first?

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.1you can deal with distributive property first or you can settle the coefficients by making the right hand side and left hand side have the same value of coefficients

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.1please do not give out answers

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but if I do the substitution method wouldn't I need to do something else first? @nincompoop

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.1substitution method how?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0its more like 3^(2x) = 7^ (x1)

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.1did you learn about logarithms yet?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes but it makes no sense

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.1use this \(\large log(a^b) = b~log(a) \)

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.1dw:1437603054834:dw

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.1no do the log first

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so the logs are in front of the numbers?

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.1please read this page then proceed with your problem later http://www.mathsisfun.com/algebra/exponentslogarithms.html

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0will you still help me

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.1maybe, but read and take notes first

freckles
 one year ago
Best ResponseYou've already chosen the best response.2Here is an example: \[5^x=6^{2x+3} \\ \text{ take } \log( ) \text{ of both sides } \\ \log(5^x)=\log(6^{2x+3}) \\ \text{ we do this so we can use } \log(r^x)=x \log(r) \text{ this is called power rule } \\ \text{ so bringing the powers down } \\ x \log(5)=(2x+3) \log(6) \\ \text{ distribute on the right hand side } \\ x \log(5)=2x \log(6)+3 \log(6) \\ \text{ now collect your terms with } x \text{ on one side } \\ x \log(5)2x \log(6)=3 \log(6) \text{ I just subtracted } 2x \log(6) \text{ on both sides } \\ \text{ now we are going to factor the } x \text{ out on the left } \\ x(\log(5)2 \log(6))=3 \log(6) \\ \text{ now we are going to divide both sides by what } x \\ \text{ is being multiplied by } \\ x=\frac{3 \log(6)}{\log(5)2 \log(6) }\] Can you show what you have doing just this step: so you try taking the log of both sides and bringing down the powers. ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0omgoodness thank you so much

freckles
 one year ago
Best ResponseYou've already chosen the best response.2Did you want to show me the one step I was mentioning? Like taking log of both sides then bringing down the powers as a result of using the power rule for log?
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