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anonymous
 one year ago
Tyler has a rectangular garden that measures 10 m wide by 13 m long. He wants to increase the area to 208 m2 by increasing the width and length by the same amount. What will be the width (shorter dimension) of the new garden?
A.
13 m wide
B.
14 m wide
C.
15 m wide
D.
16 m wide
anonymous
 one year ago
Tyler has a rectangular garden that measures 10 m wide by 13 m long. He wants to increase the area to 208 m2 by increasing the width and length by the same amount. What will be the width (shorter dimension) of the new garden? A. 13 m wide B. 14 m wide C. 15 m wide D. 16 m wide

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you know what when i first got on here today i hade 9 medals now i have 45 lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0lol you deserve them all and more

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how much did you have before the BIG test?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry but what do you mean? c:

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i think 60 something c:

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0k i am back @pinkbubbles

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0The original gardens has these dimensions. dw:1437601075655:dw

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0dw:1437601140143:dw

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0The original garden has dimensions 13 m by 10 m. If you increase both the length and the width by x meters, what are the new length and width?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh i know what it is 13m right ;)

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0dw:1437601335029:dw

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0Since the area of the new rectangle is length * width, we multiply x + 13 by x + 10. The new area is 208, so we set the new area equal to 208, and we solve for x. (x + 13)(x + 10) = 208 \(x^2 + 10x + 13x + 130 = 208\) \(x^2 + 23x  78 = 0\) \((x  3)(x + 26) = 0\) \(x  3 = 0\) or \(x + 26 = 0\) \(x = 3 \) or \(x = 26\) Since the increase in length and width cannot be 26 m, it must be 3 m. The original width was 10 m. 10 m + 3 m = 13 m The new width is 13 m. Check: The width became 13 m, and the length became 13 m + 3 m = 16 m \((13 ~m)(16 ~m) = 208 ~m^2\) 13 m is correct.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0Yes, you are correct.
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