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- anonymous

Five times the number of test tubes in a school's chemistry lab exceeds three times the number of beakers it has by 660. The sum of 2 times the number of test tubes and five times the number of beakers is 450.
If b is the number of beakers and t is the number of test tubes, what is the system of linear equations representing the situation? How many beakers are in the school lab? How many test tubes are in the school lab?

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- anonymous

- schrodinger

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- anonymous

do you have any idea how to solve?

- anonymous

No @Deeezzzz

- anonymous

using t= test tubes b= beakers
Okay can't we say that
5t=3b+660

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- anonymous

and
2t+5b=450

- anonymous

2t+5b=450
5t=3b+660
then we just solve the linear equations and solve for t and b respectively

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