anonymous
  • anonymous
I will fan please helppppp!
Geometry
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
how do I find the perimeter of the shape
taramgrant0543664
  • taramgrant0543664
It depends on the shape but you normally add up the sides
taramgrant0543664
  • taramgrant0543664
Which shape do you have in question?

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anonymous
  • anonymous
1 Attachment
taramgrant0543664
  • taramgrant0543664
For that one you can just add up the lengths of the sides but keep in mind the two sides that are angled you would have to find their length by finding the slope which is found by rise/run
anonymous
  • anonymous
so do i write -4 over 1, Im confused
anonymous
  • anonymous
i will be back in 20
taramgrant0543664
  • taramgrant0543664
I sort of said it wrong it's not slope I always just got to slope be you would use pathegorean theorem for the two sides so 3^2+4^2=c^2 so the length would be root 13 so the perimeter would be root 13 + root 13 +6+6
taramgrant0543664
  • taramgrant0543664
So the perimeter would be 12+2sqrt13 or 19.21
anonymous
  • anonymous
im back
anonymous
  • anonymous
so you would round it up and the perimeter is 19
taramgrant0543664
  • taramgrant0543664
After rounding to a whole number I would say it is 19
anonymous
  • anonymous
if you dont mind can you help me on one more and I will give you a medal
taramgrant0543664
  • taramgrant0543664
Sure
anonymous
  • anonymous
The equation of line AB is y=-1/6x-1. Write and equation of a line perpendicular to line AB in slope-intercept form that contains point(-4,3)(Hint:y-y1=M(x-x1)
taramgrant0543664
  • taramgrant0543664
Sorry my iPad decided to close this on me. The line perpendicular is the opposite slope so the perpendicular line to y=-1/6x-1 is y=1/6x+1

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