I will fan please helppppp!

- anonymous

I will fan please helppppp!

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- anonymous

The equation of line AB is y=-1/6x-1. Write and equation of a line perpendicular to line AB in slope-intercept form that contains point(-4,3)(Hint:y-y1=M(x-x1)

- jdoe0001

what's the slope of line AB?

- anonymous

idk that is everything that came with the equation

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## More answers

- jdoe0001

http://4.bp.blogspot.com/-2hRw4bmioCw/Ut8B2Kcq_8I/AAAAAAAAAi4/dRwSEZQdAHw/s1600/Slope-Intercept+Form.gif <--- notice the example, notice the slope
so... what do you think would be the slope of AB then?

- anonymous

is it -7

- jdoe0001

ahemmm... check the picture, or your book, on the slope-intercept form
since that's what y=-1/6x-1 is in

- anonymous

no this is an example on a lesson online I don't get it

- freckles

The slope of line AB is given since the line AB is given.
You can find the answer to which @jdoe0001 seeks by comparing
your line y=-1/6*x-1 to y=m*x+b.
y=m*x+b is called slope-intercept form because it tells you the slope m and the y-intercept b.

- anonymous

so is x -4/3

- freckles

not entirely sure what you are answering just now
but I was asking for the slope of y=-1/6*x-1
notice this is in slope-intercept form
it tells you the slope and the y-intercept
all you have to do is compare
y=-1/6*x-1
to
y=m*x+b
can you identify the slope m (compare the two lines) ?

- anonymous

y=-4*x+3 <------is this it

- freckles

y=-1/6*x-1
upon comparing this to
y=m*x+b
you should see m=-1/6
the slope of line AB (y=-1/6*x-1) is -1/6
--
now to find the slope of the perpendicular line
just solve the following \[\text{ Solve the following for } m_1 \text{ which I'm going to call the slope } \\ \text{ of the perpendicular line } \\ m \cdot m_1=-1 \\ \text{ where we found } m=\frac{-1}{6} \\ \frac{-1}{6} \cdot m_1=-1 \]
---
one you have found that
your perpendicular line in point-slope form will be:
\[y-y_1=m_1(x-x_1) \\ \text{ where you are given } (x_1,y_1) \text{ as } (-4,3)\]

- anonymous

m1=-7 correct

- freckles

how did you get -7?

- anonymous

-4-3

- freckles

did you try solving the equation I gave at all?

- freckles

you want to isolate m_1
try multiplying both sides by what it is being divided by
try multiplying both sides by -6

- anonymous

yeah I was trying to figure what m1 was so i could multiply by -1/6

- freckles

instead of solving that equation
you could also ask yourself what is the opposite reciprocal of -1/6

- freckles

opposite means:
The opposite of a is -a
The opposite of -a is a.
You just take the number and change the sign to find the opposite.
reciprocal means (if it exists) :
The reciprocal of a is 1/a.
The reciprocal of 1/a is a.
You just take the number and flip it.
So if I say find the opposite reciprocal of -1/6, this means you will change sign and also flip.

- anonymous

multiply -4 and 3 by 6

- anonymous

you know what I'll give you a medal for helping, but clearly this is not going through to my head so I will just guess

- freckles

I know you can find the opposite reciprocal of -1/6...
Just change the sign and then flip.

- freckles

Changing the sign...
it is negative, make it positive 1/6
now flip it, 6/1 or also known as 6.
The slope of the perpendicular line is 6.
You could have also solved that equation I gave.
\[\frac{-1}{6} m_1=-1 \\ \text{ multiply both sides by -6 } \\ (-6) \frac{-1}{6} m_1=(-6)(-1) \\ \text{ notice } \frac{6}{6}=1 \\ (- \cancel{6})\frac{-1}{\cancel{6}}m _1=(-6)(-1) \\ \text{ also recall } (-)(-)=+ \\ +m_1=+(6)(1) \\ \text{ so we have } m_1=6\]

- anonymous

m1=6 is the equation of a line perpendicular to line AB in slope-intercept

- freckles

no

- freckles

that is just the slope of the perpendicular line

- freckles

I gave the perpendicular line in point-slope form above
all you have to do is plug in numbers into it

- anonymous

oh wait so is it -4/3*6=-1

- freckles

no I don't know where you got that from but -4/3*6 isn't -1
isn't -24/3 which is -8

- anonymous

where did you get those numbers from

- freckles

I think you are looking for what I typed above
where I gave you the point slope form of the perpendicular line which was:
\[y-y_1=m_1(x-x_1) \\ \text{ where you are given } (x_1,y_1) \text{ as } (-4,3)\]

- anonymous

the question I posted says to use those numbers Write and equation of a line perpendicular to line AB in slope-intercept form that contains point(-4,3)

- freckles

once you enter in the numbers above
like you found m_1 and you are given x_1 and y_1
you can write in slope-intercept form
which is
y=slope*x+(y-intercept)
y=m_1*x+b

- anonymous

so it is y=m_1*-4-3

- freckles

you found m_1 to be 6
replace m_1 with 6
you are given x_1 as -4
replace x_1 with -4
you are given y_1 as 3
replace y_1 with 3

- anonymous

so the answer after solving equation is -42

- freckles

no
you are suppose to get an equation

- freckles

I will give the equation in point-slope form one more time
\[y-y_1=m_1(x-x_1) \]

- freckles

replace m_1 with 6
replace x_1 with -4
replace y_1 with 3

- anonymous

so its y-3=6(x+4)

- freckles

yes now just put in slope-intercept form

- freckles

distribute
and add 3 on both sides

- freckles

have to go
peace

- anonymous

@freckles answer is 42 correct

- freckles

no
y-3=6(x+4) is a line
you cannot go from a line to just a numerical value like 42
slope-intercept is of the form
y=mx+b
just use distributive property on 6(x+4)
then add the 3 on both sides

- anonymous

@freckles 3*6+4*3

- freckles

do you know the distribute property?
if you have a(b+c)
then distributive property says this is a*b+a*c

- freckles

so if you have 6(x+4) then what does distributive property say about this?

- anonymous

I thought I knew what it meant so is it 6*x+4*x @freckles

- freckles

6(x+4) by distributive property we can rewrite this as 6*x+6*4
or 6x+24
so you have
y-3=6(x+4)
y-3=6x+24
now add 3 on both sides
y=6x+24+3
y=6x+27

- freckles

this is of the form y=mx+b which we call slope-intercept form

- freckles

y=6x+27 is a line that is perpendicular to y=-1/6x-1 and also goes through the point (-4,3)

- anonymous

@freckles thank you so much no one gave me such a clear response as you and helped me get it. thank you again

- freckles

Well hopefully this will be a good example on how to do other similar problems.

- freckles

Way to hang in there. I know math can be tough but you can get it with practice and more practice.

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