A total of $20,000 is invested in two bonds that pay 8% and 9.5% in interest. The annual interest is $1675. How much is invested in each bond?

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A total of $20,000 is invested in two bonds that pay 8% and 9.5% in interest. The annual interest is $1675. How much is invested in each bond?

Mathematics
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x = amount invested at 8% 20000-x= amount invested at 9.5%
How does 2000-x equal to 9.5%?

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Other answers:

it's 20000-x
Yeah sorry that.
.08x = interest earned on 8% investment .095(20000-x)= interest earned on 9.5% investment
Total interest earned is $1675 Write and solve the equation that says the sum of the two interest amounts is1675
.08x + .095(20000-x) = $1675
Solve it.
0.08x + 0.095(20000-x) = 1675 0.08x + 1900 + 0.095x = 1675 0.175x + 1900 = 1675 0.175x = -375 2142?
-.095x
For what? Why is it negative?
\[.095(20000-x)=1900-.095x\]
oh yeah
0.705x = 1675 x = 2375
\[.08x+.095(20000-x)=1675\] \[.08x+1900-.095x=1675\] \[-.015x+1900=1675\] \[-.015x=-225\] \[\frac{-.015x}{-.015}=\frac{-225}{-.015}\] \[x=15000\]
I am sorry. I am really tired so I can't focus as usual. I have to get it on track. :)
So 15000 was invested at 8% 20000-x=5000 = amount invested at 9.5%
x= 15000
So those are the answers right?

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