What is the missing side length of an irregular pentagon with side lengths nineteen point nine centimeters, twenty-four point eight centimeters, thirty centimeters and forty-nine point two centimeters, if the perimeter is equal to the perimeter of a regular hexagon with side length twenty-six centimeters?

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What is the missing side length of an irregular pentagon with side lengths nineteen point nine centimeters, twenty-four point eight centimeters, thirty centimeters and forty-nine point two centimeters, if the perimeter is equal to the perimeter of a regular hexagon with side length twenty-six centimeters?

Mathematics
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19.9cm 24.8cm 30cm 49.2cm and \(x\)cm (\(x\) is the missing side-length) ----------------------------------- Now, the perimiter of this shape is equal to the perimeter of a regular hexagon with side length twenty-six centimeters. Lets find this "perimeter of regular hexagon w/ side length 26 centimeters", hexagon = 6 sides each side is 26, so all sides are 26•6=156 So the perimeter of our initial shape is 156
Now, all you need to do is to find the missing side. Perimeter = The sum of all of the sides. 156 = 19.9 + 24.8 + 30 + 49.2 + \(x\) And knowing all sides except one, and after we have found the sum, we have to solve for x (x is the missing side).
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