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Say I choose a random point on there (x,y)
such that x^2+y^2=1

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And I draw a right triangle

Thank you this is helping!

and remember this circle has radius 1
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cos(theta)=x/1=x
sin(theta)=y/1=y

\[\cos^2(\theta)+\sin^2(\theta)=1 \text{ is a Pythagorean identitiy }\]

Oh! I see!

Fantastic, thank you! Could you explain how identities might look on a graph?

Thank you so so much sir!!!!

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