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Have you heard of SOHCAHTOA?
Hint: it ends in a decimal
Use the parts of SOHCAHTOA of the sine and the cosine.
I hate to tell you this, but it doesn't.
Did I make a mistake then?
what is the opposite side of angle A
This type of triangle with the 90degrees and the 45degrees is a special type of triangle. Isosceles, i think. This means that the 7 side and the y side are always equal. the 45degrees and the unlabeled angle are the same, because the angles of the triangle add to 180. so, 180 - 90 -45 = 45. the unknown angle is 45degrees. Which also proves that the sides, 7 and y are the same length. Then to find x, you can use Pathagorean's theorem. (spelling?) ... which says C2=A2+B2 where C is the hypotenuse (across from the right angle), and A and B are the other sides. So, for your problem, x2=72+72=49+49=98 x=98−−√
an isosceles triangle has two sides of the same length, this one does not
Then Using SOHCAHTOA hypotenuse = opposite / sin x = 7 / sin45 x = 9.9 adjacent = opposite / tan y = 7 / tan45 y = 7 Or using Pythagoras Theorem. A right angle triangle with two 45 degree angles means that two sides are the same. Therefore y also equals 7. a^2 = b^2 + c^2 where a is the hypotenuse. x^2 = 7^2 + 7^2 x^2 = 49 + 49 x^2 = 98 x = 9.9
I am redeeming myself....I guess I did it wrong sorry guys.
For a right triangle, the sin of the angle is the ratio of the opposite side divided by the hypotenuse side lengths
the sin of A would simply be 48/50
I should have set up another challenge
I messed up, why???
oh, you are trying to challenge the panel maybe?, so you already know these things then
oh, this is my fault, sorry
they need a new tab section, for these type questions