When a 2.5 mol of sugar (C12H22O11) are added to a certain amount of water the boiling point is raised by 1 Celsius degree. If 2.5 mol of aluminum nitrate is added to the same amount of water, by how much will the boiling point be changed? Show all calculations leading to your answer OR use 3 – 4 sentences to explain your answer.

Hey! We 've verified this expert answer for you, click below to unlock the details :)

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

\[DeltaT = iK _{b}m \] i = the vast hoff factor which is how many moles of ions are dissolved. m = molality moles of solute/kilogram of solution i believe. Kb = a constant what your solvent is.

I'm not completely sure but i'll do my best. 1. know the moles of sucrose 2. we know the temperature change 3. we know Kb we must find molality So that would be deltaT/(Kb*i) = m \[(1)/(0.52)(1) = 2 = m \] we know that we used 2.5 moles and molality is moles of solute/kg solvent 2 = 2.5mol/kg solute we do some math and we got 1.25 kg of solvent H2O \[Al(NO3_{3}) ---> 3NO _{3} + AL ^{3+}\] i'm not sure but you need to figure out how many moles of ions that are dissolved. so you have 3 moles of the nitrate and 1 mole of the aluminum so 3+1 = 4 for i I guess for the reaction with sugar that's 2.5 mol of sugar. and i = 1 but you're adding this to the other solution so i think you would need to take into account the sucrose as well. i = 5 kb =0.52 m = 5.0 moles/1.25 kg = 4 mol/kg ions. You would need to plug all these into your formula

@Cuanchi I may have missed something

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

Looking for something else?

Not the answer you are looking for? Search for more explanations.