What is the approximate length of the base of an isosceles triangle if the congruent sides are 2.5 m and the vertex angle is 25°?

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What is the approximate length of the base of an isosceles triangle if the congruent sides are 2.5 m and the vertex angle is 25°?

Mathematics
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okay so what do i do
use trigonometry to find x|dw:1437623905930:dw| I think you need the cosine ratio
i dont know what to do ?

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Other answers:

1.08 m 2.62 m 3.37 m impossible to tell
when you find the value of x, just double it as the perpendicular from the angle to the base bisects the base
|dw:1437624049817:dw|
so its 2.62
|dw:1437624104059:dw|
x = 77.5° the base is equal to 2* 2.5 cos(77.5°)
4 4√2 8 8√2 these are my options

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