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anonymous
 one year ago
Describe the end behavior of the graph for each function.
1) f(x)=x^3+2x^25x+1
2) g(x)=2x^38x^2+18x+72
anonymous
 one year ago
Describe the end behavior of the graph for each function. 1) f(x)=x^3+2x^25x+1 2) g(x)=2x^38x^2+18x+72

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do you remember the correlation between the highest degree of a polynomial and its end behaviour?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yep! i'm just not sure how to properly describe it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0would i just say down on the left and up on the right? is that correct for 1?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0could i use the infinity signs or would that not work for this??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Or the graph is going negative when going to the left, and positive when going to the right.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You can use infinity signs. Infinity signs would actually be more accurate.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how would i write that?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That really depends.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I will show you what i mean.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow \infty} = \infty\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow \infty} = \infty \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It is a calculus concept.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You would use both of them.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay i think i get it! thank you so much :)
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