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anonymous

  • one year ago

how would the graph of f=kq/r^2 , look like?

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  1. anonymous
    • one year ago
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    @Luigi0210

  2. anonymous
    • one year ago
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    |dw:1437629460998:dw|

  3. anonymous
    • one year ago
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    this is the answer but how ?

  4. anonymous
    • one year ago
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    i unserstand that now

  5. anonymous
    • one year ago
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    one arrow is going north and the other east

  6. anonymous
    • one year ago
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    so the resulatent would be north of east

  7. anonymous
    • one year ago
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    yes vector logic

  8. anonymous
    • one year ago
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    how can somone not know this lol

  9. anonymous
    • one year ago
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    so can u help me with this question?

  10. anonymous
    • one year ago
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    lol ik this is graph its rectangular hyperbola

  11. anonymous
    • one year ago
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    f is inversely proportional to r^2

  12. anonymous
    • one year ago
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    idk how to explain further .

  13. anonymous
    • one year ago
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    can u help me with another question?

  14. anonymous
    • one year ago
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    i cant try

  15. anonymous
    • one year ago
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    |dw:1437630051924:dw|

  16. anonymous
    • one year ago
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    a positive rod is brouhgt near but not touching

  17. anonymous
    • one year ago
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    a neutral ball

  18. anonymous
    • one year ago
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    what charge will the X become?

  19. anonymous
    • one year ago
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    the other will acquire positive charge

  20. anonymous
    • one year ago
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    can u explian

  21. anonymous
    • one year ago
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    y will get negatively charged on bringing positive charge near it so x will get positively charged so that ball remains neutral

  22. anonymous
    • one year ago
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    got it ?

  23. anonymous
    • one year ago
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    when we do these types of question we have to remeber to keep the ball neutral?

  24. anonymous
    • one year ago
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    yes if it was neutral but if the ball is charged then thats a different case

  25. anonymous
    • one year ago
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    i have few more question do u mind?

  26. anonymous
    • one year ago
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    yes ask

  27. anonymous
    • one year ago
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    radio waves from space longer thn 1/10th the diameter of the radio telescope are undetebale on earths surface , waht is the frequency?

  28. anonymous
    • one year ago
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    idk this one

  29. anonymous
    • one year ago
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    ok heres another

  30. anonymous
    • one year ago
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    A unit combination equivalment to tesla is ?

  31. anonymous
    • one year ago
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    the anwer is kg/As^2 , not sure why

  32. anonymous
    • one year ago
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    The tesla (symbolized T) is the standard unit of magnetic flux density. It is equivalent to one weber per meter squared (1 Wb. m -2 ). Reduced to base units in the International System of Units ( SI ), 1 T represents one kilogram per second squared per ampere (kg

  33. anonymous
    • one year ago
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    got it ?

  34. anonymous
    • one year ago
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    ok yea

  35. anonymous
    • one year ago
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    1 Attachment
  36. anonymous
    • one year ago
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    this one

  37. anonymous
    • one year ago
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    is it a ?

  38. anonymous
    • one year ago
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    no

  39. anonymous
    • one year ago
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    then ?

  40. anonymous
    • one year ago
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    d

  41. anonymous
    • one year ago
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    u know right hand cross rule ?

  42. anonymous
    • one year ago
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    its left hand cause electron

  43. anonymous
    • one year ago
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    logic

  44. anonymous
    • one year ago
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    yes the force on electron will decide the direction in which it will move .thr force can be found out by using left hand rule

  45. anonymous
    • one year ago
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    got it ?

  46. anonymous
    • one year ago
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    ye

  47. anonymous
    • one year ago
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    ok

  48. anonymous
    • one year ago
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    studying for unit test is long and hard

  49. anonymous
    • one year ago
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    work it harder make it better , our work is never over

  50. anonymous
    • one year ago
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    yea best of luck

  51. anonymous
    • one year ago
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    who is taht other guy?

  52. anonymous
    • one year ago
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    who ?

  53. anonymous
    • one year ago
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    stalker lol

  54. anonymous
    • one year ago
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    how long r u gonna stay here

  55. anonymous
    • one year ago
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    idk

  56. anonymous
    • one year ago
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    cuz i am going to work more probs so might have more probs to ask later

  57. anonymous
    • one year ago
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    idk .u can pm me i will reply or fan me to see if i m online or not

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