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I practically already know (How) to get the answer, I just need to make it look like this::

|dw:1437655413905:dw|

And it says to drag numbers out of the box and place the apropiately in the boxes

That's what it tells me to do

Did you find the area of the "small" segment?

yES

dO YOU WANT IT

Woops. Caps lock again

yes

Okay. Gimmee a sec

|dw:1437655965362:dw|

There you go.

ok.
the area on the other side of the chord
|dw:1437656246763:dw|

the area of the entire circle \( \pi \ r^2\) = \( 64 \pi\)

Okay

I would simplify that

\[ 64 \pi - \left( \frac{64 \pi}{6} - 16 \sqrt{3}\right) \\
64 \pi -\frac{64 \pi}{6} + 16 \sqrt{3}\]

So we use distribution?

distribution would "undo" the factoring out. Instead, simplify (6-1)

So 5

yes. also, we can divide top and bottom by 2

That would make the 5 uneven

you have
\[ \frac{5 \cdot 64 \pi}{6} + 16 \sqrt{3} \]
you can divide the 6 by 2 and the 64 by 2

Oh that makes sense

So 32 and 3?

now you have to fill in your boxes with those numbers

Okay. Thanks that really helps

And btw,

Is there any way to possibly save conversations for future reference?

You could save the link ... I don't think OS will delete this post.
Or maybe take screen shots?

Yeah, but this really isn't my personal computer though

Maybe I'll just save the link to my Google Docs account then

yes, save the link.

I will

Thanks for the medal