## anonymous one year ago ***WILL MEDAL AND FAN*** Express answer in exact form. Find the area of the larger segment whose chord is 8" long in a circle with an 8" radius. (Hint: A chord divides a circle into two segments. In problem 1, you found the area of the smaller segment.)

1. anonymous

I practically already know (How) to get the answer, I just need to make it look like this::

2. anonymous

|dw:1437655413905:dw|

3. anonymous

And it says to drag numbers out of the box and place the apropiately in the boxes

4. anonymous

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the correct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag the item to the trashcan. Click the trashcan to clear all your answers.

5. anonymous

That's what it tells me to do

6. phi

Did you find the area of the "small" segment?

7. anonymous

yES

8. anonymous

dO YOU WANT IT

9. anonymous

Woops. Caps lock again

10. phi

yes

11. anonymous

Okay. Gimmee a sec

12. anonymous

|dw:1437655965362:dw|

13. anonymous

There you go.

14. phi

ok. the area on the other side of the chord |dw:1437656246763:dw|

15. phi

the area of the entire circle $$\pi \ r^2$$ = $$64 \pi$$

16. phi

thus you want to do area of circle - area of segment $64 \pi - \left( \frac{64 \pi}{6} - 16 \sqrt{3}\right)$

17. anonymous

Okay

18. phi

I would simplify that

19. phi

$64 \pi - \left( \frac{64 \pi}{6} - 16 \sqrt{3}\right) \\ 64 \pi -\frac{64 \pi}{6} + 16 \sqrt{3}$

20. phi

multiply the first term by 6/6 $\frac{6}{6} \cdot 64 \pi - \frac{64 \pi}{6} + 16 \sqrt{3}\\ \frac{6\cdot 64 \pi - 64 \pi}{6} + 16 \sqrt{3}$ can you finish?

21. phi

to make it easier, I would "factor out" 64 pi so it looks like this $\frac{(6 -1) 64 \pi}{6} + 16 \sqrt{3}$

22. anonymous

So we use distribution?

23. phi

distribution would "undo" the factoring out. Instead, simplify (6-1)

24. anonymous

So 5

25. phi

yes. also, we can divide top and bottom by 2

26. anonymous

That would make the 5 uneven

27. phi

you have $\frac{5 \cdot 64 \pi}{6} + 16 \sqrt{3}$ you can divide the 6 by 2 and the 64 by 2

28. anonymous

Oh that makes sense

29. anonymous

So 32 and 3?

30. phi

yes, so we now have $\frac{5 \cdot 32 \pi}{3} + 16 \sqrt{3}$ 32 is 2*2*2*2*2 so we can't divide any more. multiply 5*32 to get 160 and the final version is $\frac{160}{3} \pi+ 16 \sqrt{3}$

31. phi

now you have to fill in your boxes with those numbers

32. anonymous

Okay. Thanks that really helps

33. anonymous

And btw,

34. anonymous

Is there any way to possibly save conversations for future reference?

35. phi

You could save the link ... I don't think OS will delete this post. Or maybe take screen shots?

36. anonymous

Yeah, but this really isn't my personal computer though

37. anonymous

Maybe I'll just save the link to my Google Docs account then

38. phi

39. anonymous

I will

40. anonymous

Thanks for the medal