***WILL MEDAL AND FAN*** Express answer in exact form. Find the area of the larger segment whose chord is 8" long in a circle with an 8" radius. (Hint: A chord divides a circle into two segments. In problem 1, you found the area of the smaller segment.)

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***WILL MEDAL AND FAN*** Express answer in exact form. Find the area of the larger segment whose chord is 8" long in a circle with an 8" radius. (Hint: A chord divides a circle into two segments. In problem 1, you found the area of the smaller segment.)

Mathematics
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I practically already know (How) to get the answer, I just need to make it look like this::
|dw:1437655413905:dw|
And it says to drag numbers out of the box and place the apropiately in the boxes

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Other answers:

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the correct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag the item to the trashcan. Click the trashcan to clear all your answers.
That's what it tells me to do
  • phi
Did you find the area of the "small" segment?
yES
dO YOU WANT IT
Woops. Caps lock again
  • phi
yes
Okay. Gimmee a sec
|dw:1437655965362:dw|
There you go.
  • phi
ok. the area on the other side of the chord |dw:1437656246763:dw|
  • phi
the area of the entire circle \( \pi \ r^2\) = \( 64 \pi\)
  • phi
thus you want to do area of circle - area of segment \[ 64 \pi - \left( \frac{64 \pi}{6} - 16 \sqrt{3}\right) \]
Okay
  • phi
I would simplify that
  • phi
\[ 64 \pi - \left( \frac{64 \pi}{6} - 16 \sqrt{3}\right) \\ 64 \pi -\frac{64 \pi}{6} + 16 \sqrt{3}\]
  • phi
multiply the first term by 6/6 \[ \frac{6}{6} \cdot 64 \pi - \frac{64 \pi}{6} + 16 \sqrt{3}\\ \frac{6\cdot 64 \pi - 64 \pi}{6} + 16 \sqrt{3} \] can you finish?
  • phi
to make it easier, I would "factor out" 64 pi so it looks like this \[ \frac{(6 -1) 64 \pi}{6} + 16 \sqrt{3} \]
So we use distribution?
  • phi
distribution would "undo" the factoring out. Instead, simplify (6-1)
So 5
  • phi
yes. also, we can divide top and bottom by 2
That would make the 5 uneven
  • phi
you have \[ \frac{5 \cdot 64 \pi}{6} + 16 \sqrt{3} \] you can divide the 6 by 2 and the 64 by 2
Oh that makes sense
So 32 and 3?
  • phi
yes, so we now have \[ \frac{5 \cdot 32 \pi}{3} + 16 \sqrt{3} \] 32 is 2*2*2*2*2 so we can't divide any more. multiply 5*32 to get 160 and the final version is \[ \frac{160}{3} \pi+ 16 \sqrt{3} \]
  • phi
now you have to fill in your boxes with those numbers
Okay. Thanks that really helps
And btw,
Is there any way to possibly save conversations for future reference?
  • phi
You could save the link ... I don't think OS will delete this post. Or maybe take screen shots?
Yeah, but this really isn't my personal computer though
Maybe I'll just save the link to my Google Docs account then
  • phi
yes, save the link.
I will
Thanks for the medal

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