A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
graph 6x^2 +11x  35
anonymous
 one year ago
graph 6x^2 +11x  35

This Question is Closed

MrNood
 one year ago
Best ResponseYou've already chosen the best response.0this is a quadratic equation  its graph is a parabola if you want to sketch it then if the value in front of x is positive then it is U shaped, if negative then it is inverted U If you set x = 0 in the equatin  that will give oyu the vlue where it crosses the Y axis if you solve the quadrtic =0 then that will give you the place where it crosses the X axis that is enough to sketch it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.06x^2 + 11x 35 = 0 Factor. To do this, Multiply 35 and 6 and get 210, Now what two numbers multiply to 210 and add up to 11 (the coefficient of the middle term)? Answer 21 and 10 So break the 11x into two terms. 6x^2 + 21x 10x 35 = 0 Group (6x^2 + 21x) + (10x 35) = 0 Factor like terms 3x(2x + 7) + 5(2x + 7) = 0 Then factor out the (2x + 7) for (2x + 7)(3x  5) = 0 so set each term = 0 and get x = 5/3 or x = 7/2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.06x² + 11x  35 = 0 6x²  10x + 21x  35 = 0 2x(3x  5) + 7(3x  5) = 0 (3x  5) (2x + 7) = 0 3x  5 = 0 OR 2x + 7 = 0 x = 5/3 or x = 7/2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.06x^2 + 11x 35 = 0 6x^2 10x + 21x 35 = 0 2x(3x5)+7(3x5)=0 (2x+7)(3x5)=0 2x=7 or 3x=5 x=7/2 or x=5/3
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.