A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
What are the factors of x2  81?
(x + 9)(x  9)
(x  9)(x  9)
(x + 3)(x  27)
Prime
anonymous
 one year ago
What are the factors of x2  81? (x + 9)(x  9) (x  9)(x  9) (x + 3)(x  27) Prime

This Question is Closed

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0difference of square s \[\huge\rm a^2  b^2 = (a+b)(ab)\]

pooja195
 one year ago
Best ResponseYou've already chosen the best response.0Diffrence of squares \[\huge~\rm~\sqrt{ x^2}=\sqrt{81}\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0take square root of both term write your answer in two parenthses (sqrt of first term + sqrt of 2nd term )( sqrt of first term  sqt of 2nd term )

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You can use foil here & just work backwards aswell, so looking at answer choice #1, (x+9)(x9) "F" first: X * X = X^2 "O" outside: X * 9 = 9x "I" inside: 9 * X = 9x "L" last: 9 * (9) = 81 So you have: x^2 + 9x  9x 81 Now simplify: x^2 81 Thats how i solved my equations in school. hope it helps :)

Mehek14
 one year ago
Best ResponseYou've already chosen the best response.0what do you think is the answer?

Mehek14
 one year ago
Best ResponseYou've already chosen the best response.0no 9 * 9 = +81 not 81

Mehek14
 one year ago
Best ResponseYou've already chosen the best response.0it would be (x + 9)(x  9)

Mehek14
 one year ago
Best ResponseYou've already chosen the best response.0because x*x = \(x^2\) \(9x+9x=0\\9*9=81\\x^2+081\\x^281\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh ok i think i get it now
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.