anonymous
  • anonymous
Subtract and simplify: (3x2 + 5x – 4) – (2x2 – 7x – 1) A. 5x2 – 2x – 3 B. x2 + 12x – 3 C. –x2 + 12x – 5 D. –x2 – 2x – 3
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
@pinkbubbles
anonymous
  • anonymous
is this the question? \[(3x^2+5x-4)-(2x^2-7x-1)\]
anonymous
  • anonymous
yes it is :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
okay! :)
anonymous
  • anonymous
Stack the too equations and work it out. 3x^2 + 5x - 4 - 2x^2 - 7x - 1 what do you get by subtracting those two?
anonymous
  • anonymous
remember subtracting the x's does not get rid of them, for example: 3x^2 - 2x^2 = x^2
anonymous
  • anonymous
\[x^2 + 12x - 3\]
anonymous
  • anonymous
(((3•(x2))+5x)-4)-(((2•x2)-7x)-1)
anonymous
  • anonymous
Raise x to the 2nd power
anonymous
  • anonymous
so it is B ok
anonymous
  • anonymous
\[(((3 • x^2) + 5x) - 4) - (2x^2 - 7x - 1)\]
anonymous
  • anonymous
Yes! c:
anonymous
  • anonymous
yes it is :)
anonymous
  • anonymous
\[3x^2+5x-4 - 2x^2-7x-1\]
anonymous
  • anonymous
Anyways you get it right? :)
anonymous
  • anonymous
and thank you as well @yungjvke
anonymous
  • anonymous
HEY PINK I DID IT i did the 2 medal thing lol
anonymous
  • anonymous
YAY! i wonder if other people know how to do it?

Looking for something else?

Not the answer you are looking for? Search for more explanations.