## -Welp- one year ago http://i.imgur.com/nNBSO6j.png Find the side of x.

1. -Welp-

|dw:1437667599289:dw|

2. SolomonZelman

you can use the Pythagorean theorem to find the x. This theorem says, that if your triangle is a right triangle, then the sides of these triangle will satisfy the following equation: a² + b² = c² where c is the hypotenuse.

3. -Welp-

30 is the angle, not the side.

4. SolomonZelman

oh, my fault...

5. SolomonZelman

30º is complementary with the angle above x, (lets name it gº)

6. SolomonZelman

that means that gº+30º=90º So the angle above x (angle gº as I named it) is equal to ?

7. -Welp-

60

8. SolomonZelman

yes. this gº is 60º. So then the angle far to the left (lets name it wº) can be found using the fact that the sum of all angles in a triangle (in any triangle) is equal to 180º.

9. SolomonZelman

Your angles are gº , 90º , wº you have found the gº=60º So your angles are 60º , 90º , wº and as in any triangle, they sum must be equal to 180º, so lets write that: 60º + 90º + wº = 180º

10. SolomonZelman

can you solve for w?

11. SolomonZelman

Then use the sign law $$\Large \dfrac{x}{\sin(w^\circ)}=\dfrac{19}{\sin(g^\circ)}$$ (remember that: 1. g is your angle obve the x, that is 60º 2. w is your left-most angle that is (you have to find that) and plug this information in into the above sign law) good luck

12. -Welp-

$\frac{ x }{ \sin 30 } =\frac{ 19 }{ \sin 60 }$ $9/\sin 60 = \frac{ \sqrt{3} }{ 2 }$ Okay, I have no idea what else to do.

13. amoodarya

another way |dw:1437671160595:dw|