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-Welp-

  • one year ago

http://i.imgur.com/nNBSO6j.png Find the side of x.

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  1. -Welp-
    • one year ago
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    |dw:1437667599289:dw|

  2. SolomonZelman
    • one year ago
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    you can use the Pythagorean theorem to find the x. This theorem says, that if your triangle is a right triangle, then the sides of these triangle will satisfy the following equation: a² + b² = c² where c is the hypotenuse.

  3. -Welp-
    • one year ago
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    30 is the angle, not the side.

  4. SolomonZelman
    • one year ago
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    oh, my fault...

  5. SolomonZelman
    • one year ago
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    30º is complementary with the angle above x, (lets name it gº)

  6. SolomonZelman
    • one year ago
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    that means that gº+30º=90º So the angle above x (angle gº as I named it) is equal to ?

  7. -Welp-
    • one year ago
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    60

  8. SolomonZelman
    • one year ago
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    yes. this gº is 60º. So then the angle far to the left (lets name it wº) can be found using the fact that the sum of all angles in a triangle (in any triangle) is equal to 180º.

  9. SolomonZelman
    • one year ago
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    Your angles are gº , 90º , wº you have found the gº=60º So your angles are 60º , 90º , wº and as in any triangle, they sum must be equal to 180º, so lets write that: 60º + 90º + wº = 180º

  10. SolomonZelman
    • one year ago
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    can you solve for w?

  11. SolomonZelman
    • one year ago
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    Then use the sign law \(\Large \dfrac{x}{\sin(w^\circ)}=\dfrac{19}{\sin(g^\circ)}\) (remember that: 1. g is your angle obve the x, that is 60º 2. w is your left-most angle that is (you have to find that) and plug this information in into the above sign law) good luck

  12. -Welp-
    • one year ago
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    \[\frac{ x }{ \sin 30 } =\frac{ 19 }{ \sin 60 } \] \[9/\sin 60 = \frac{ \sqrt{3} }{ 2 } \] Okay, I have no idea what else to do.

  13. amoodarya
    • one year ago
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    another way |dw:1437671160595:dw|

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