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SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.0you can use the Pythagorean theorem to find the x. This theorem says, that if your triangle is a right triangle, then the sides of these triangle will satisfy the following equation: a² + b² = c² where c is the hypotenuse.

Welp
 one year ago
Best ResponseYou've already chosen the best response.030 is the angle, not the side.

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.030º is complementary with the angle above x, (lets name it gº)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.0that means that gº+30º=90º So the angle above x (angle gº as I named it) is equal to ?

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.0yes. this gº is 60º. So then the angle far to the left (lets name it wº) can be found using the fact that the sum of all angles in a triangle (in any triangle) is equal to 180º.

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.0Your angles are gº , 90º , wº you have found the gº=60º So your angles are 60º , 90º , wº and as in any triangle, they sum must be equal to 180º, so lets write that: 60º + 90º + wº = 180º

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.0can you solve for w?

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.0Then use the sign law \(\Large \dfrac{x}{\sin(w^\circ)}=\dfrac{19}{\sin(g^\circ)}\) (remember that: 1. g is your angle obve the x, that is 60º 2. w is your leftmost angle that is (you have to find that) and plug this information in into the above sign law) good luck

Welp
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ x }{ \sin 30 } =\frac{ 19 }{ \sin 60 } \] \[9/\sin 60 = \frac{ \sqrt{3} }{ 2 } \] Okay, I have no idea what else to do.

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.0another way dw:1437671160595:dw
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