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Ibbutibbu.

  • one year ago

༼ つ ◕_◕ ༽つ PLEASE HELP ME ༼ つ ◕_◕ ༽つ

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  1. Ibbutibbu.
    • one year ago
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  2. Ibbutibbu.
    • one year ago
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    I need help with the 3rd question

  3. anonymous
    • one year ago
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    2pm−1q0(2m−1p3) 2pq2 = 4p4 2m2pq2 = 4p3 2m2q2 = 2p3 m2q2

  4. Ibbutibbu.
    • one year ago
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    thats... really confusing

  5. Ibbutibbu.
    • one year ago
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    can you perhaps use that button down there that says equation?

  6. anonymous
    • one year ago
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    \[2p^3/m^2q^2\]

  7. anonymous
    • one year ago
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    2p^3 all over m^2q^2

  8. Ibbutibbu.
    • one year ago
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    the method, can you do that in the equation form?

  9. Ibbutibbu.
    • one year ago
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    ???

  10. anonymous
    • one year ago
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    \[ 4p^4/ 2m^2pq^2\] and then simply that too \[\frac{ 4p^3 }{ 2m^2q^2 }\]

  11. anonymous
    • one year ago
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    then divide the 4 by 2 and you get your answer

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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