anonymous
  • anonymous
PLZ HELP WILL MEDAL AND FAN \Use the squares to help you find a reasonable range for the area of the circle. Show your work. A circle is placed on a grid of squares, each one unit by one unit. A square that is 5 units by 5 units fits completely inside the circle. The circle fits completely inside a square that is 9 units on each side.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
https://racine.brainhoney.com/Resource/26948139,0/Assets/flvs/math1_v10_gs-xml/res0118/08_tb_08_015.jpg
anonymous
  • anonymous
@paki
JoannaBlackwelder
  • JoannaBlackwelder
Ok, what is the area of the square that the circle fits inside?

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More answers

anonymous
  • anonymous
25
Flvs.net
  • Flvs.net
I'll help.
JoannaBlackwelder
  • JoannaBlackwelder
And what is the area of the other square?
anonymous
  • anonymous
what other square
JoannaBlackwelder
  • JoannaBlackwelder
The one that is 9 units on each side
anonymous
  • anonymous
i see 7 x 7
JoannaBlackwelder
  • JoannaBlackwelder
|dw:1437673370828:dw| Sorry for the poorly drawn squares
JoannaBlackwelder
  • JoannaBlackwelder
Oh, in the words, it says 9 units
anonymous
  • anonymous
oh never mind, 81
JoannaBlackwelder
  • JoannaBlackwelder
But yeah, in the pic, it looks like just over 7 to me as well.
JoannaBlackwelder
  • JoannaBlackwelder
So, what do you think that tells us about the range of the area of the circle?
anonymous
  • anonymous
um I am nor sure
JoannaBlackwelder
  • JoannaBlackwelder
Well, since a 25 units^2 square fits completely inside the circle, it has to be greater than 25 units^2
JoannaBlackwelder
  • JoannaBlackwelder
Does that idea make sense?
anonymous
  • anonymous
so it has to be greater than 25 but less than 81
JoannaBlackwelder
  • JoannaBlackwelder
Yep
JoannaBlackwelder
  • JoannaBlackwelder
If we go by the 9 in the words
anonymous
  • anonymous
so it could be 50
JoannaBlackwelder
  • JoannaBlackwelder
Yeah, that is one option.
anonymous
  • anonymous
oh okay thanks
JoannaBlackwelder
  • JoannaBlackwelder
You're welcome :-)

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