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anonymous

  • one year ago

Write the converse of the conditional statement and state whether it is true or false. If a number is a whole number, then it is an integer. A. If a number is not a whole number, then it is not an integer. The converse is false. B. If a number is an integer, then it is a whole number. The converse is false. C. If a number is not an integer, then it is not a whole number. The converse is true. D. If a number is not an integer, then it is a whole number. The converse is false.

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  1. anonymous
    • one year ago
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    @amoodarya

  2. anonymous
    • one year ago
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    @amoodarya

  3. anonymous
    • one year ago
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    I believe it is C

  4. anonymous
    • one year ago
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    @mathstudent55

  5. anonymous
    • one year ago
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    @Jadeishere

  6. anonymous
    • one year ago
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    thank you for coming to help me @mathstudent55

  7. mathstudent55
    • one year ago
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    Statement: If p then q. Converse: If q then p. Statement: If hypothesis, then conclusion. Converse: If conclusion, then hypothesis. To find the converse of an "if statement", you must first identify the hypothesis and the conclusion. Then switch their positions.

  8. anonymous
    • one year ago
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    then it would be C right

  9. mathstudent55
    • one year ago
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    Choice C. has "not" added to the hypothesis and the conclusion. Do you see any "not" in the original statement?

  10. mathstudent55
    • one year ago
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    Look in the original statement. Here it is: \(\Large \sf If ~a ~number ~is ~a ~whole ~number, ~then ~it ~is ~an ~integer.\) What is the hypothesis? What is the conclusion?

  11. anonymous
    • one year ago
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    what about B then?

  12. mathstudent55
    • one year ago
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    The hypothesis is red, and the conclusion is green. Do you agree? \(\Large \sf If ~\color{red}{a ~number ~is ~a ~whole ~number}, ~then ~\color{green}{it ~is ~an ~integer}.\)

  13. anonymous
    • one year ago
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    yes

  14. mathstudent55
    • one year ago
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    Now switch them. You may need to slightly modify the language for the sentence to make sense. \(\Large \sf If~\color{green}{it ~is ~an ~integer} , ~then ~\color{red}{a ~number ~is ~a ~whole ~number}.\) Now we slightly adjust the language: \(\Large \sf If~\color{green}{~a ~number ~is ~an ~integer} , ~then ~\color{red}{~it ~is ~a ~whole ~number}.\)

  15. anonymous
    • one year ago
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    so it's sctually D

  16. mathstudent55
    • one year ago
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    No. D again has "not" in it. You were correct before. The answer is B. You can't add "not". You can only switch the hypothesis and the conclusion.

  17. anonymous
    • one year ago
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    oo ok yea i was kind of confused and thanks

  18. mathstudent55
    • one year ago
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    You're welcome.

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