anonymous
  • anonymous
Did i do this right?? (x-^2y^-4x^3)-^2 First remove the parenthesis now we use the ab = 1/ab property x^-2 = 1/x^2 now we have a positive exponent x^2. Next y^-4 = 1/y^4 now we have three positive exponents now we need to make the negative 2 positive. -2= 1/-2 now we have x^2y^4x^3 add the like terms x^2+ x^3 = x^5 (x^5y^4)^2
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
have u ever heard PEMDAS in math
anonymous
  • anonymous
Yes i did
anonymous
  • anonymous
use that to solve it did u do that

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anonymous
  • anonymous
I believe so.
mathstudent55
  • mathstudent55
Is this the problem? \(\Large (x^{-2}y^{-4}x^3)^{-2}\)
anonymous
  • anonymous
do it again and show me the steps and ill correct u if ur wrong

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