• anonymous
Did i do this right?? (x-^2y^-4x^3)-^2 First remove the parenthesis now we use the ab = 1/ab property x^-2 = 1/x^2 now we have a positive exponent x^2. Next y^-4 = 1/y^4 now we have three positive exponents now we need to make the negative 2 positive. -2= 1/-2 now we have x^2y^4x^3 add the like terms x^2+ x^3 = x^5 (x^5y^4)^2
Mathematics
• Stacey Warren - Expert brainly.com
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