## anonymous one year ago More help on polynomails

1. anonymous

The second part of the new coaster is a parabola. Ray needs help creating the second part of the coaster. Create a unique parabola in the pattern f(x) = ax2 + box + c. Describe the direction of the parabola and determine the y-intercept and zeros. The safety inspector notes that Ray also needs to plan for a vertical ladder through the center of the coaster's parabolic shape for access to the coaster to perform safety repairs. Find the vertex and the equation for the axis of symmetry of the parabola, showing your work, so Ray can include it in his coaster plan. Create a graph of the polynomial function you created in Question 4.

2. anonymous

Too lazy babe

4. anonymous

Oh god lol

5. automaticloveletter

A for effort. :)

6. anonymous

Umm ok lol

7. anonymous

@ganeshie8

8. anonymous

@jamesr @ROMNAY

9. anonymous

yolo

10. anonymous

Yeah crazy ik

11. anonymous

I can do the graph on my own all I need is an example for the equation its asking me to make

12. anonymous

@ganeshie8 @phi

13. automaticloveletter

Good luck xD

14. anonymous

3 hours later

15. automaticloveletter

What?

16. anonymous

That I will be here 3 hours later

17. automaticloveletter

That is me when no one helps me xD

18. anonymous

ikr lol

19. anonymous

so who what where aand how

20. automaticloveletter

Or just choose whatever.

21. anonymous

Its not multiply choice all I need is help on this part I can do the rest: Ray needs help creating the second part of the coaster. Create a unique parabola in the pattern f(x) = ax2 + box + c. Describe the direction of the parabola and determine the y-intercept and zeros.

22. automaticloveletter

No I meant I usually just choose whatever if no one answers.

23. automaticloveletter

And I put whatever for the essay points xD

24. anonymous

wow.....

25. anonymous

lol this teacher wants everything done correctly she is super annoying I really need this done @jane11509

26. anonymous

@automaticloveletter thx i for got and whatever my answer is freaking MARIO

27. anonymous

Wow well.... I need help on this I am confused.

28. anonymous

@BeginnerCountrySinger

29. BeginnerCountrySinger

Ew graphs

30. automaticloveletter

I don't mean whatever, I just put what I think is the answer or just leave that part out.

31. anonymous

I don't need the graph part I can do that on my own like I said all I need is this part: Ray needs help creating the second part of the coaster. Create a unique parabola in the pattern f(x) = ax2 + box + c. Describe the direction of the parabola and determine the y-intercept and zeros

32. anonymous

Auto I can't do that Like I said my teacher would just make me do it again until I get it right

33. automaticloveletter

Damn she sucks then. Mine says the same but I don't do it. Most of the time I try my hardest.

34. anonymous

Mine is a pain in the arse I swear she doesn't let me pass if I get a 60 in my final test she wants me to get at least a 70 -.-

35. anonymous

finally getting help on pa I am closing thos out

36. automaticloveletter

I've heard that the high school teachers are a pain on FLVS.

37. anonymous

They are

38. automaticloveletter

#Prayforyou

39. phi

Create a unique parabola in the pattern f(x) = ax2 + box + c. Describe the direction of the parabola and determine the y-intercept and zeros the "y-intercept" is the number you get when x is 0 $f(0)= a\cdot 0^2 + 0\cdot x + c \\ f(0)= c$ so the "last number" will be the y-intercept. The "zeros" are the x values where the parabola crosses the x-axis (i.e. y=0) the easiest way to find the zeros is to start by *pick the zeros in advance* and then create the equation using those numbers.

40. anonymous

wow finally

41. phi

the first step is pick the two zeros. pick two numbers (but not 0 or we won't get a "c" )

42. anonymous

What do you mean by pick 2 zeros?

43. phi

a parabola looks like |dw:1437677924836:dw|

44. anonymous

OH OK.... ok I choose 3 and 6

45. phi

so at x=3 and x=6 your parabola will be at the x-axis x=3 --> (x-3)=0 x=6 --> (x-6)=0 multiply (x-3)(x-6)= 0 if we multiply by some number "a" we get a(x-3)(x-6)= 0 if you make a negative, it will make the shape $$\cap$$ that is the equation of how to find the zeros of a parabola after we factored it. now we work backwards. First multiply out (x-3)(x-6)

46. anonymous

ok but there is nothing to multiply outside..... 18x????

47. automaticloveletter

I knew you'd get help!!!

48. phi

Have you learned FOIL ?

49. anonymous

I take flvs they don't teach you anything nope teach me foil

50. phi

FOIL is a way to remember how to do this. The "correct way" is to "distribute" say you had the problem A(x-6) do you know how to distribute the A (multiply each term inside the parens by A)?

51. anonymous

What? I am so sorry I am giving you a hard time I am bad at math and this is a last minuet assigment my teacher gave me....