Bo factored x2 – 10xy + 16y2 as follows: Line 1 x2 – 10xy + 16y2 Line 2 x2 – 8xy – 2xy + 16y2 Line 3 x(x – 8) – 2y(x – 8y) Line 4 prime A. Did Bo correctly factor the polynomial? Justify your response by explaining why it is is factored correctly or by showing the correct solution if it is not factored correctly. B. Explain how you would know if a polynomial of the form ax2 + bxy + cy2 was prime.

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Bo factored x2 – 10xy + 16y2 as follows: Line 1 x2 – 10xy + 16y2 Line 2 x2 – 8xy – 2xy + 16y2 Line 3 x(x – 8) – 2y(x – 8y) Line 4 prime A. Did Bo correctly factor the polynomial? Justify your response by explaining why it is is factored correctly or by showing the correct solution if it is not factored correctly. B. Explain how you would know if a polynomial of the form ax2 + bxy + cy2 was prime.

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Bo didnt because the correct way is x(x – 8y) – 2y(x – 8y) then the best solution will be x2 – 10xy + 16y2 = (x - 2y) (x - 8y) it is not prime b) ax2 + bxy + cy2 was prime? if both a and c are prime then the polynomial is prime like X2+5 is prime
line 2 and 3 are wrong
In the last step he made x^2-8xy into x(x-8), when he really should have made it into x(x-8y), resulting the factored polynomials to be...(x-8y)(x-2y).

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