anonymous
  • anonymous
Evaluate the series 50 + 10 + 2 + . . .
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
I'm confused as to what "Evaluate" actually means. Answer choices: A) 62 B) 1/5 C) The series diverges; it does not have a sum D) 62.5
SolomonZelman
  • SolomonZelman
you divide by 5 every time. you start from 50 so you can write it as \(\large\color{black}{ \displaystyle \sum_{ n=0 }^{ \infty } ~ \dfrac{50}{5^n}}\)
SolomonZelman
  • SolomonZelman
this series definitely converges, will you give me that?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Yeah
SolomonZelman
  • SolomonZelman
you can find the exact sum because it is geometric...
SolomonZelman
  • SolomonZelman
\(\Large\displaystyle\sum_{ n=0 }^{ \infty } ~ 50(1/5)^n=\frac{50}{1-\frac{1}{5}}=?\)
anonymous
  • anonymous
we would get 125/2 or 62.5. Thanks. Is there any place where i could get a quick refresher on Geometric and arithmetic series?
anonymous
  • anonymous
That is correct

Looking for something else?

Not the answer you are looking for? Search for more explanations.