tmagloire1
  • tmagloire1
AP Calculus AB Help!! Medals I need help on 2 questions http://prntscr.com/7w7cjp http://prntscr.com/7w7cul
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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SolomonZelman
  • SolomonZelman
Ok, lets do the question 1 first.
SolomonZelman
  • SolomonZelman
inflection point is an x-value that makes f''(x)=0, so the f'(x) doesn't tell us anything about the inflection points. So you can eliminate C, and it should be a critical point/number. A critical number is when f'(x)=0. When is this the case, when x=1, or x=0?
tmagloire1
  • tmagloire1
When x=0

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SolomonZelman
  • SolomonZelman
yes, correct, so your answer is...
tmagloire1
  • tmagloire1
A!
SolomonZelman
  • SolomonZelman
yes, the first option.
SolomonZelman
  • SolomonZelman
now, question #2 ...
tmagloire1
  • tmagloire1
Thanks an okay
SolomonZelman
  • SolomonZelman
See where x=-2.25 and x=-1.75 are on your graph?
tmagloire1
  • tmagloire1
Yes
SolomonZelman
  • SolomonZelman
this part of the graph you can take alone (and ignore the rest of the graph) to tell me the approximate slope at x=-2.
tmagloire1
  • tmagloire1
Don't they land in the middle of a box? How can I find the approx. slope?
SolomonZelman
  • SolomonZelman
You can just visually tell me, if you refer to your options....
SolomonZelman
  • SolomonZelman
you have no function f(x) given in a form of an equation, i know, but you can take that piece from x=-1.75 to x=-2.25, and tell me what the slope of this whole peace is appaorximately
tmagloire1
  • tmagloire1
2
tmagloire1
  • tmagloire1
oops not an option
SolomonZelman
  • SolomonZelman
take a narrower space on the function at about x=-2, and try to picture what a tangent line would look like
tmagloire1
  • tmagloire1
I still can't really see it. I'm just doing rise/run to count the slope on the graph is this wrong. I'm not really understanding it
SolomonZelman
  • SolomonZelman
it is correct, but you are taking a too wide interval.... i can't copy your picture..... wanted to show something but my extention for copying it isn't there...
SolomonZelman
  • SolomonZelman
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SolomonZelman
  • SolomonZelman
|dw:1437686429195:dw|
SolomonZelman
  • SolomonZelman
|dw:1437686484177:dw|
SolomonZelman
  • SolomonZelman
We can go ahead and find the function it you want tho'
tmagloire1
  • tmagloire1
Is the smaller approx. 1
SolomonZelman
  • SolomonZelman
yes, yes !
SolomonZelman
  • SolomonZelman
Very nice...
tmagloire1
  • tmagloire1
if you go from -1.75 to -2
tmagloire1
  • tmagloire1
Oh okay lol idk why that was so hard for me sorry
SolomonZelman
  • SolomonZelman
you can take like -1.9 to -2.1
tmagloire1
  • tmagloire1
Thank you for your help though!
tmagloire1
  • tmagloire1
Okay but isn't the actual answer closer to +1 not -1
tmagloire1
  • tmagloire1
Ohh okay I thought -3/4 for a was the approximation
SolomonZelman
  • SolomonZelman
it is not 1, because the graph is squiized, it is more likely a 4.
tmagloire1
  • tmagloire1
oh ok
SolomonZelman
  • SolomonZelman
yeah, if you were to stretch the graph so that ever unit of x and unit of y get the same space, then the slope is way greater than 1, so the answer is 4, actually...
tmagloire1
  • tmagloire1
okay thank you!

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