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tmagloire1

  • one year ago

AP Calculus AB Help!! Medals I need help on 2 questions http://prntscr.com/7w7cjp http://prntscr.com/7w7cul

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  1. SolomonZelman
    • one year ago
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    Ok, lets do the question 1 first.

  2. SolomonZelman
    • one year ago
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    inflection point is an x-value that makes f''(x)=0, so the f'(x) doesn't tell us anything about the inflection points. So you can eliminate C, and it should be a critical point/number. A critical number is when f'(x)=0. When is this the case, when x=1, or x=0?

  3. tmagloire1
    • one year ago
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    When x=0

  4. SolomonZelman
    • one year ago
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    yes, correct, so your answer is...

  5. tmagloire1
    • one year ago
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    A!

  6. SolomonZelman
    • one year ago
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    yes, the first option.

  7. SolomonZelman
    • one year ago
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    now, question #2 ...

  8. tmagloire1
    • one year ago
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    Thanks an okay

  9. SolomonZelman
    • one year ago
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    See where x=-2.25 and x=-1.75 are on your graph?

  10. tmagloire1
    • one year ago
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    Yes

  11. SolomonZelman
    • one year ago
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    this part of the graph you can take alone (and ignore the rest of the graph) to tell me the approximate slope at x=-2.

  12. tmagloire1
    • one year ago
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    Don't they land in the middle of a box? How can I find the approx. slope?

  13. SolomonZelman
    • one year ago
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    You can just visually tell me, if you refer to your options....

  14. SolomonZelman
    • one year ago
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    you have no function f(x) given in a form of an equation, i know, but you can take that piece from x=-1.75 to x=-2.25, and tell me what the slope of this whole peace is appaorximately

  15. tmagloire1
    • one year ago
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    2

  16. tmagloire1
    • one year ago
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    oops not an option

  17. SolomonZelman
    • one year ago
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    take a narrower space on the function at about x=-2, and try to picture what a tangent line would look like

  18. tmagloire1
    • one year ago
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    I still can't really see it. I'm just doing rise/run to count the slope on the graph is this wrong. I'm not really understanding it

  19. SolomonZelman
    • one year ago
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    it is correct, but you are taking a too wide interval.... i can't copy your picture..... wanted to show something but my extention for copying it isn't there...

  20. SolomonZelman
    • one year ago
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    |dw:1437686303764:dw|

  21. SolomonZelman
    • one year ago
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    |dw:1437686429195:dw|

  22. SolomonZelman
    • one year ago
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    |dw:1437686484177:dw|

  23. SolomonZelman
    • one year ago
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    We can go ahead and find the function it you want tho'

  24. tmagloire1
    • one year ago
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    Is the smaller approx. 1

  25. SolomonZelman
    • one year ago
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    yes, yes !

  26. SolomonZelman
    • one year ago
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    Very nice...

  27. tmagloire1
    • one year ago
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    if you go from -1.75 to -2

  28. tmagloire1
    • one year ago
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    Oh okay lol idk why that was so hard for me sorry

  29. SolomonZelman
    • one year ago
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    you can take like -1.9 to -2.1

  30. tmagloire1
    • one year ago
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    Thank you for your help though!

  31. tmagloire1
    • one year ago
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    Okay but isn't the actual answer closer to +1 not -1

  32. tmagloire1
    • one year ago
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    Ohh okay I thought -3/4 for a was the approximation

  33. SolomonZelman
    • one year ago
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    it is not 1, because the graph is squiized, it is more likely a 4.

  34. tmagloire1
    • one year ago
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    oh ok

  35. SolomonZelman
    • one year ago
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    yeah, if you were to stretch the graph so that ever unit of x and unit of y get the same space, then the slope is way greater than 1, so the answer is 4, actually...

  36. tmagloire1
    • one year ago
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    okay thank you!

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