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ashking1
 one year ago
Find the zeros of the polynomial function and state the multiplicity of each.
f(x) = 4(x + 7)2(x  7)3
ashking1
 one year ago
Find the zeros of the polynomial function and state the multiplicity of each. f(x) = 4(x + 7)2(x  7)3

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ashking1
 one year ago
Best ResponseYou've already chosen the best response.1these are the choices 4, multiplicity 1; 7, multiplicity 3; 7, multiplicity 3 7, multiplicity 3; 7, multiplicity 2 4, multiplicity 1; 7, multiplicity 1; 7, multiplicity 1 7, multiplicity 2; 7, multiplicity 3 can someone help me please

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.0do you mean ?\[f(x) = 4(x + 7)^2(x  7)^3\]

phi
 one year ago
Best ResponseYou've already chosen the best response.2you should put in ^ to show exponents. I assume this is f(x) = 4(x + 7)^2(x  7)^3 \[ f(x) = 4(x + 7)^2(x  7)^3 \]

phi
 one year ago
Best ResponseYou've already chosen the best response.2what happens if you erase the x and put in 7 in its place in (x7) what number do you get ?

phi
 one year ago
Best ResponseYou've already chosen the best response.2yes. they use the word "multiplicity" so look for an answer that says 7 multiplicity 3

ashking1
 one year ago
Best ResponseYou've already chosen the best response.17, multiplicity 3; 7, multiplicity 2 so would this be the answer

phi
 one year ago
Best ResponseYou've already chosen the best response.2it is easy to get confused. 4(x + 7)^2(x  7)^3 we did (x7) . what x makes that zero?

ashking1
 one year ago
Best ResponseYou've already chosen the best response.1what do you mean by that like its the second x the one that says in (x7) and if x is 7 it will equal 0 right ?

phi
 one year ago
Best ResponseYou've already chosen the best response.2(x7) is zero when x=7 and multiplicity 3 because we have (x7)^3

phi
 one year ago
Best ResponseYou've already chosen the best response.2you picked *** 7, multiplicity 2 so would this be the answer***

ashking1
 one year ago
Best ResponseYou've already chosen the best response.1it would be 7, multiplicity 2; 7, multiplicity 3

ashking1
 one year ago
Best ResponseYou've already chosen the best response.1thanks btw can you help me with one more

ashking1
 one year ago
Best ResponseYou've already chosen the best response.1i need help understanding either the triangle or the theorem to answer this question Expand the following using either the Binomial Theorem or Pascal’s Triangle. You must show your work for credit. (x  5)5

ashking1
 one year ago
Best ResponseYou've already chosen the best response.1like you dont have to tell me the answer more like help me understand how to get there

phi
 one year ago
Best ResponseYou've already chosen the best response.2please use the ^ otherwise it looks like (x5) times 5 you mean \( (x5)^5 \) first, write it like this: \( (x + (5) )^5 \)

phi
 one year ago
Best ResponseYou've already chosen the best response.2next, we start with this pattern \[ (a+b)^5 = a b + a b + a b + ...\] make the exponent of the a in the first term 5, and the exponent on b 0 (the exponents will *always* add up to 5) the next a will have an exponent of 4 (and the b will have 1) can you write out the a b pattern for (a+b)^5 ?

ashking1
 one year ago
Best ResponseYou've already chosen the best response.1so it will be (5+0)^5= (4)(1).....

phi
 one year ago
Best ResponseYou've already chosen the best response.2no. I am trying to say that \[ (a+b)^5 = a^5 b^0 + a^4 b^1 + ... \] (there are also numbers we have to put in, but first we need to learn how to write down this pattern) can you finish writing out the full pattern ?

ashking1
 one year ago
Best ResponseYou've already chosen the best response.1would the next one be like a^3b^2

phi
 one year ago
Best ResponseYou've already chosen the best response.2you mean a^2 b^3 (remember the exponents add up to 5) or the a goes down, the one on b goes up

ashking1
 one year ago
Best ResponseYou've already chosen the best response.1ya sorry thats what i ment

phi
 one year ago
Best ResponseYou've already chosen the best response.2keep going, we need all the terms

phi
 one year ago
Best ResponseYou've already chosen the best response.2yes. so we have (so far) \[ (a+b)^5 = a^5 b^0 + a^4 b^1 + a^3b^2+a^2b^3 + a^1 b^4 +a^0 b^5\] now we have to put in coefficients (numbers) in front of each term. we use Pascal's triangle to find these numbers.

phi
 one year ago
Best ResponseYou've already chosen the best response.2start by writing this pattern dw:1437687651177:dw

phi
 one year ago
Best ResponseYou've already chosen the best response.2next we add a new row by adding 1 on each side, and adding the two numbers in the row above it. Like this dw:1437687710434:dw

phi
 one year ago
Best ResponseYou've already chosen the best response.2now we keep adding rows until we get to a row with 6 entries... that will be the row we will use. dw:1437687767682:dw

phi
 one year ago
Best ResponseYou've already chosen the best response.2can you find the next row ?

ashking1
 one year ago
Best ResponseYou've already chosen the best response.1dw:1437687781164:dw

ashking1
 one year ago
Best ResponseYou've already chosen the best response.1i seen it before but how does it help for the problem

phi
 one year ago
Best ResponseYou've already chosen the best response.2and we add those to our pattern \[ (a+b)^5 = 1a^5 b^0 +5 a^4 b^1 + 10a^3b^2+10a^2b^3 + 5a^1 b^4 +1a^0 b^5 \]

phi
 one year ago
Best ResponseYou've already chosen the best response.2we can simplify that a little... a^0 and b^0 are both 1. And we can leave off a coefficient of 1. so the pattern can be \[ (a+b)^5 = a^5 +5 a^4 b + 10a^3b^2+10a^2b^3 + 5a b^4 +b^5 \]

phi
 one year ago
Best ResponseYou've already chosen the best response.2now we can tackle your problem \[ (x + (5) )^5 \] every where you see a in the pattern , replace it with x and replace b with (5) can you do that ?

ashking1
 one year ago
Best ResponseYou've already chosen the best response.1i changed everyhthing

phi
 one year ago
Best ResponseYou've already chosen the best response.2they probably want you to multiply out the (5) to each exponent

phi
 one year ago
Best ResponseYou've already chosen the best response.2the first two terms should be \[ x^5  25x^4 ...\]

ashking1
 one year ago
Best ResponseYou've already chosen the best response.1sorry im writing everything on a piece of paper

ashking1
 one year ago
Best ResponseYou've already chosen the best response.1+250x^3 is the next one right

phi
 one year ago
Best ResponseYou've already chosen the best response.2last 3125 is ok but redo 5*x*(5)^4

phi
 one year ago
Best ResponseYou've already chosen the best response.2yes. so put it together for the final answer.

ashking1
 one year ago
Best ResponseYou've already chosen the best response.1\[x^525x^4+250x^31250x^2+3125x3125\]

ashking1
 one year ago
Best ResponseYou've already chosen the best response.1thats the answer right
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