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anonymous
 one year ago
A rectangle has sides measuring (6x + 4) units and (2x + 11) units.
Part A: What is the expression that represents the area of the rectangle? Show your work to receive full credit.
Part B: What are the degree and classification of the expression obtained in Part A?
Part C: How does Part A demonstrate the closure property for polynomials?
anonymous
 one year ago
A rectangle has sides measuring (6x + 4) units and (2x + 11) units. Part A: What is the expression that represents the area of the rectangle? Show your work to receive full credit. Part B: What are the degree and classification of the expression obtained in Part A? Part C: How does Part A demonstrate the closure property for polynomials?

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0best answer gets fan and medal

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So the area of a rectangle is equal to both sides multiplied together so you get A=(6x+4)(2x+11). Next you need to multiply this out, that is multiply all terms in one bracket by all terms in the other bracket, this gives you A = 6x*2x +4*2x + 6x*11 + 4*11, which is then A=12x^2 +74x +44, thats part a done. The degree is simply the highest power in this case 2 and its called a quadratic equation... I think that's what is meant by classification (not sure)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm just looking up closure

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So closure under an operation simply means that if you put two things into the operation you get the same kind of thing out. In this case you put two polynomials of degree 1 in and you get one polynomial of degree 2 out, part a exemplified closure of polynomials under multiplication
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