A food company distributes its tomato soup in two cans of different sizes. For the larger can, both the diameter and the height have been increased by
By what percentage does the volume of the can increase from the smaller can to the larger can? Round your answer to the nearest percent.
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Small can volume = (π*r^2) height
Large can volume = (π*1.3r^2) height
you can give r and height all the values you want, and compare them, to make it simple, we can try with 1and 2
SCV = (π*1^2) 2 = 6.2831
LCV = (π*1.3(1)^2) = 10.6185
Then you only have to calculate the percentage of the growth.
10.6185 - 6.2831 = 4.3354
4.3354 = 68.96%
Percentage of growth = 69 %
ok, you could have guessed it was 69%, my result was 68.96 cause I didn't use all the decimal numbers I should have used.