anonymous
  • anonymous
help i will fan and medal answer already solved need to figure out out how she got the numbers
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
I sort of said it wrong it's not slope I always just got to slope be you would use pathegorean theorem for the two sides so 3^2+4^2=c^2 so the length would be root 13 so the perimeter would be root 13 + root 13 +6+6 12+2sqrt13
anonymous
  • anonymous
someone already helped me on this but idk where she got the numbers from
anonymous
  • anonymous
this is the equation she solved find the perimeter of the shape
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More answers

anonymous
  • anonymous
@Skielerlucas04 can you help or do you know anyone who can
anonymous
  • anonymous
@blackeistien238821 help please
anonymous
  • anonymous
idk wut grade work dis
anonymous
  • anonymous
geometry 10th grade
anonymous
  • anonymous
i only 7th grade sorry
anonymous
  • anonymous
wish i could help
anonymous
  • anonymous
oh it thanks but do you know any that can help me
anonymous
  • anonymous
jim_thompson5910
anonymous
  • anonymous
@jim_thompson5910
anonymous
  • anonymous
i think she got the numbers from the points but used slope intercep form to find the length of the sides
anonymous
  • anonymous
so how did she get the numbers from slope intercept
jim_thompson5910
  • jim_thompson5910
Focus on the right triangle I have drawn in red. This triangle has legs of 2 and 3.
jim_thompson5910
  • jim_thompson5910
a = 2 b = 3 c = unknown a^2 + b^2 = c^2 2^2 + 3^2 = c^2 solve for c to get c = ???
anonymous
  • anonymous
15
anonymous
  • anonymous
sorry 12
jim_thompson5910
  • jim_thompson5910
nope on both
anonymous
  • anonymous
13
jim_thompson5910
  • jim_thompson5910
2^2 + 3^2 = c^2 4 + 9 = c^2 c^2 = 13 c = ??
anonymous
  • anonymous
what do i do with 13
anonymous
  • anonymous
13 times 13 is 169
jim_thompson5910
  • jim_thompson5910
the opposite actually, you take the square root of 13
jim_thompson5910
  • jim_thompson5910
\[\Large c = \sqrt{13}\]
anonymous
  • anonymous
that 3.605551275
anonymous
  • anonymous
4
jim_thompson5910
  • jim_thompson5910
The length of AB is \(\Large \sqrt{13}\) units long. The same reasoning applies to CD.
anonymous
  • anonymous
or 4 lol
anonymous
  • anonymous
i got 4 for CD
anonymous
  • anonymous
@jim_thompson5910
jim_thompson5910
  • jim_thompson5910
CD is the same length as AB
anonymous
  • anonymous
but how did she get 19
jim_thompson5910
  • jim_thompson5910
both are exactly sqrt(13) units long they are approximately 3.60555127546399 units long
jim_thompson5910
  • jim_thompson5910
I don't see any 19
anonymous
  • anonymous
like what IIIIIIIIIIIIIIIIII said
anonymous
  • anonymous
12+2sqrt13 equals 19
jim_thompson5910
  • jim_thompson5910
I'd have to see the full problem + instructions
anonymous
  • anonymous
19 was the final answer
jim_thompson5910
  • jim_thompson5910
Oh nvm, you're looking for the perimeter
jim_thompson5910
  • jim_thompson5910
two sides are 6 6+6 = 12
jim_thompson5910
  • jim_thompson5910
the other two sides are \[\Large \sqrt{13}\]
jim_thompson5910
  • jim_thompson5910
\[\Large \sqrt{13}+\sqrt{13} = 2\sqrt{13}\]
anonymous
  • anonymous
how are they 6
jim_thompson5910
  • jim_thompson5910
Perimeter = \(\Large 12+2\sqrt{13} \approx 19.2111025509\) which rounds to 19
jim_thompson5910
  • jim_thompson5910
BC = AD = 6
jim_thompson5910
  • jim_thompson5910
you just count the spaces for the horizontal or vertical segments
anonymous
  • anonymous
oh ok
jim_thompson5910
  • jim_thompson5910
|dw:1437692895844:dw|
anonymous
  • anonymous
were is 13 from
jim_thompson5910
  • jim_thompson5910
|dw:1437692932875:dw|
jim_thompson5910
  • jim_thompson5910
it's not just 13. It's the square root of it
anonymous
  • anonymous
why cant it be sqrt 12 or another number why is it 13
jim_thompson5910
  • jim_thompson5910
because that's what you get when you solve for c in 2^2 + 3^2 = c^2
jim_thompson5910
  • jim_thompson5910
it's \(\sqrt{13}\) and NOT 13
anonymous
  • anonymous
i know
anonymous
  • anonymous
@hershey21
anonymous
  • anonymous
yep
anonymous
  • anonymous
idk lol

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