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anonymous

  • one year ago

Did i do this right? here is my problem (x – 2) (3x-4) Remove the parenthesis x times 3=3x^2. x times -4 = -4x -2* 3x^2 = -6x^2 -2* -4x= 8x Now we have -6x^2 -8x Not sure if i combine or Divide... Guessing i'll combine. -6x^2 +-8x = 14^3 <-- my answer.

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  1. Vocaloid
    • one year ago
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    not quite, let's take it from the top (x-2)(3x-4) let's multiply the first terms x*3x = 3x^2 then the outer terms x*(-4) = -4x then the inner terms (-2)*(3x) = -6x then the last (-2)*(-4) = 8 now we combine: 3x^2 - 4x - 6x + 8 = 3x^2 - 10x + 8

  2. Vocaloid
    • one year ago
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    let me know if there's anything you're still confused about

  3. jdoe0001
    • one year ago
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    \(\large (x - 2) (3x-4)\implies \begin{array}{crllll} x\cdot 3x\implies &3x^2\\ x\cdot -4\implies &-4x\\ -2\cdot 3x\implies &-6x\\ -2\cdot -4\implies &+8 \end{array}\)

  4. anonymous
    • one year ago
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    Where did the 3x^2 come from didn't we just use that to make 6x? @Vocaloid

  5. Vocaloid
    • one year ago
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    you need to use the (3x) twice

  6. Vocaloid
    • one year ago
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    (A-B)(C-D) = A*C-A*D-B*C+B*D

  7. anonymous
    • one year ago
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    Wow didn't know that one.

  8. Vocaloid
    • one year ago
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    maybe I can draw this one out? |dw:1437691175227:dw|

  9. Vocaloid
    • one year ago
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    |dw:1437691198444:dw|

  10. Vocaloid
    • one year ago
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    |dw:1437691238225:dw|

  11. Vocaloid
    • one year ago
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    |dw:1437691266501:dw|

  12. Vocaloid
    • one year ago
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    |dw:1437691303670:dw|

  13. Vocaloid
    • one year ago
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    adding everything together: 3x^2-4x-6x+8 = 3x^2-10x+8

  14. anonymous
    • one year ago
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    Alright thanks a lot for explaining.

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