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|dw:1437691840404:dw| any ideas where those two fellas are in the graph?
can you graph them there?

|dw:1437691171977:dw|

right?

wouldn't the focus be on the x-axis, not the y-axis?
since it is (2,0) not (0,2)

hmmmm hold the mayo.. .maybe .... I did mess up there, lemme recheck that

|dw:1437692548026:dw|

hmmm wait a sec.. dohh. the x coordinate can't be 0 anyhow hehe one sec

ok, we have the vertex, now what do we do to get the equation for it

just plug in the values in the parabola equation focus form

so it ends up as (x-2)^2 = 4*6(y-(-6))

Is there another way to write that out, because none of the above are answer choices

my anwer choices are x^2-4-35; -x^2+4+35; -1/24x^2+1/6x-35/6; and 1/24x^2-1/6-35/6

ok one sec

what?

any... thing.. that confuses there?

what happens to the second and third fractions

oh, ok. The would simplify to 2/12 and 35/8

sorry 1/6

oh, ok. Thanks for the help

yw