A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
solve between 0 and 2pi
cotxsin^2x=2cotx
anonymous
 one year ago
solve between 0 and 2pi cotxsin^2x=2cotx

This Question is Closed

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1\(\large { cot(x)sin^2(x)=2cot(x)\implies cot(x)sin^2(x)2cot(x)=0 \\ \quad \\ cot(x)[sin^2(x)2]=0\implies \begin{cases} cot(x)=0\\ sin^2(x)2=0 \end{cases} }\) solve those for "x", using the inverse trigonometric function, or just using your Unit Circle

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.01. Subtract 2cotx from both sides 2. Factor out cotx 3. Set each factor equal to 0 and solve each equation.

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1btw, if you didn't get the lines from surjithayer on the previous posting you can just let us know that you dunno, or what part you don't get, and maybe just explain you'd repost to get more eyes
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.