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MTALHAHASSAN2

  • one year ago

Need help!! 4. Solve for x: cos 3x=1/2 0<x<pie

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  1. Mertsj
    • one year ago
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    If you want all x solutions between 0 and pi, find all 3x solutions between 0 and 3pi

  2. Mertsj
    • one year ago
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    \[\cos (3x)=\frac{1}{2}\] \[3x=\frac{\pi}{3}, \frac{7\pi}{3},\frac{13\pi}{3}\]

  3. Mertsj
    • one year ago
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    \[x=\frac{\pi}{9},\frac{7\pi}{9}, \frac{13\pi}{9}\]

  4. Mertsj
    • one year ago
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    Whoops...one too many. Discard 13pi/9

  5. MTALHAHASSAN2
    • one year ago
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    wait how you get 7pie/3

  6. MTALHAHASSAN2
    • one year ago
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    I get pie/3

  7. MTALHAHASSAN2
    • one year ago
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    know how can I find the other solutions

  8. MTALHAHASSAN2
    • one year ago
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    Plz help me

  9. Mertsj
    • one year ago
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    Add 2pi to pi/3

  10. Mertsj
    • one year ago
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    Each time around the circle will give another solution.

  11. MTALHAHASSAN2
    • one year ago
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    don't you get 5pie/3

  12. Mertsj
    • one year ago
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    What is 1/3 + 6/3 ?

  13. MTALHAHASSAN2
    • one year ago
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    |dw:1437704060359:dw|

  14. MTALHAHASSAN2
    • one year ago
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    because in the first and fourth quardrant the cos be postive

  15. MTALHAHASSAN2
    • one year ago
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    I now that is 7pie/3

  16. MTALHAHASSAN2
    • one year ago
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    But I am talking about 5pie/3

  17. Mertsj
    • one year ago
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    Yep. \[3x=\frac{\pi}{3}, \frac{5\pi}{3}, \frac{7\pi}{3}\]

  18. Mertsj
    • one year ago
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    \[x=\frac{\pi}{9}, \frac{5\pi}{9}, \frac{7\pi}{9}\]

  19. MTALHAHASSAN2
    • one year ago
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    know that make a sence but know for the 7pie/3 we are adding 2pie+pie/3 right!!

  20. MTALHAHASSAN2
    • one year ago
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    |dw:1437704505385:dw|

  21. Mertsj
    • one year ago
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    yep

  22. MTALHAHASSAN2
    • one year ago
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    ok Thanks a lot

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