anonymous
  • anonymous
JHGJHGMNH NH H
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
i think it's D b.c range is y and 9 is Y and it's a positive 9 so it should be 9 in more? someone should check me.. please
anonymous
  • anonymous
anonymous
  • anonymous

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freckles
  • freckles
f(time)=a function of (number of video games) anyways the input time represents the domain and f(time) aka number of video games represents the range you said the domain was non-negative values values like 0,1,2,3,4,... and so on... but if f(x) = 6x + 9 then f(0)=6(0)+9=9 and f(1)=6+9=15 and so on... so yes the outputs are 9 or more
anonymous
  • anonymous
yaaaaaaaaay ! thank you :)
freckles
  • freckles
and also non-negative values can include decimal numbers but f(0)=9 and f(1/2)=6(1/2)+9=3+9=12 and f(1)=15 so anyways just trying to show it the number values are increasing starting at 9
freckles
  • freckles
replace f(x) with 3 and solve for x
freckles
  • freckles
\[f(x)=\frac{4x+1}{3} \\ f^{-1}(3)=x \text{ implies } f(x)=3 \\ \text{ so replace } f(x) \text{ with } 3 \\ 3=\frac{4x+1}{3} \\ \text{ Solve for } x \]
anonymous
  • anonymous
is it 2
freckles
  • freckles
yes 3(3)=4x+1 9=4x+1 8=4x x=2 so f(2)=3 which means \[f^{-1}(3)=2\]
anonymous
  • anonymous
alright the first question was wrong. i got a 77% on this test which is better the an D or F but thank you
freckles
  • freckles
you are saying the question you asked before the inverse question"?
freckles
  • freckles
all the options had time being non-negative f(x)=6x+9 would definitely have range y greater than or equal to 9
anonymous
  • anonymous
i guess C was it then
anonymous
  • anonymous
but its ok... i passed
freckles
  • freckles
|dw:1437704714373:dw| yep for domain x greater than or equal to 0 we definitely have range is y greater than or equal to 9 that is a visual way to look at it a algebraic way is to do the following: we are given: \[x \ge 0 \\ \text{ multiply both sides by } 6 \\ 6x \ge 0 \\ \text{ add both sides by } 9 \\ 6x+9 \ge 9 \\ f(x)=6x+9 \\ \text{ so } f(x) \ge 9 \]
freckles
  • freckles
So if they didn't have the option where the range was y greater than or equal to 9 where the domain was nonnegative real numbers then they are actually wrong
anonymous
  • anonymous
you might be right,, but its okhay lol i passed the test with an C thank youuu
freckles
  • freckles
oh I didn't know I was helping with a test.
anonymous
  • anonymous
yeah, but thank you
UsukiDoll
  • UsukiDoll
Please don't post real exam/test questions as it is against terms and conditions and openstudy has an anti-cheating policy in effect. "By using the OpenStudy Site or Service, you acknowledge that OpenStudy cooperates fully with schools, colleges and other educational institutions (together “Schools”) and reserves the right to disclose User information to a School if there is an allegation by that School of cheating or violation of the School’s academic policies. Openstudy.com will take swift action against anyone found misusing the community’s Site or Service. In addition to refunding any membership fee, we will ban Users who cheat from the Site and Service permanently." More information can be found here: http://openstudy.com/terms-and-conditions

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