anonymous
  • anonymous
What is the factored form of 64g^3 +8? Fan and Medal
Mathematics
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
anonymous
  • anonymous
the answers are below
anonymous
  • anonymous
\[a^3+b^3=\left( a+b \right)\left( a^2-ab+b^2 \right)\]

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anonymous
  • anonymous
what is a?
anonymous
  • anonymous
@surjithayer
anonymous
  • anonymous
\[64g^3=\left( 4g \right)^3\]
anonymous
  • anonymous
\[8=2^3\]
UsukiDoll
  • UsukiDoll
are you there @rose49 ?
anonymous
  • anonymous
is it d
UsukiDoll
  • UsukiDoll
\[64g^3+8\] hints: both of these terms have a number in common what is 8 x 8 ?
anonymous
  • anonymous
64
UsukiDoll
  • UsukiDoll
oh sorry this is sum of cubes. yes 8 x 8 = 64 but I misread the question by accident
UsukiDoll
  • UsukiDoll
sum of cubes formula \[(a+b)(a^2-ab+b^2) \]
UsukiDoll
  • UsukiDoll
so we need to write this equation.. what is the cube root of 8 and the cube root of 64?
anonymous
  • anonymous
2^3
campbell_st
  • campbell_st
64 = 4 x 4 x 4 g^3 = g x g x g the problem is the sum of of 2 cubes 8 = 2 x 2 x 2 so the factored form is \[a^3 + b^3 = (a + b)(a^2 -ab + b^2)\]
anonymous
  • anonymous
wouldn't it be d
UsukiDoll
  • UsukiDoll
and cube root of g^3 ?
UsukiDoll
  • UsukiDoll
\[64g^3 + 8 \rightarrow (4g)^3+2^3\] so a = 4g and b = 2 plug this into the sum of cubes equation
anonymous
  • anonymous
i did and i got the answer d was i wrong?
UsukiDoll
  • UsukiDoll
I don't think so.. I think you're right but just to be sure \[(4g+2)((4g)^2-4g(2)+4)\]
UsukiDoll
  • UsukiDoll
\[(4g+2)(16g^2-8g+4)\]
UsukiDoll
  • UsukiDoll
yeah it is d
anonymous
  • anonymous
okay thank you for the help i have one more to ask about
UsukiDoll
  • UsukiDoll
sure

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