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anonymous

  • one year ago

What is the factored form of 64g^3 +8? Fan and Medal

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    the answers are below

  3. anonymous
    • one year ago
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    \[a^3+b^3=\left( a+b \right)\left( a^2-ab+b^2 \right)\]

  4. anonymous
    • one year ago
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    what is a?

  5. anonymous
    • one year ago
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    @surjithayer

  6. anonymous
    • one year ago
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    \[64g^3=\left( 4g \right)^3\]

  7. anonymous
    • one year ago
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    \[8=2^3\]

  8. UsukiDoll
    • one year ago
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    are you there @rose49 ?

  9. anonymous
    • one year ago
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    is it d

  10. UsukiDoll
    • one year ago
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    \[64g^3+8\] hints: both of these terms have a number in common what is 8 x 8 ?

  11. anonymous
    • one year ago
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    64

  12. UsukiDoll
    • one year ago
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    oh sorry this is sum of cubes. yes 8 x 8 = 64 but I misread the question by accident

  13. UsukiDoll
    • one year ago
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    sum of cubes formula \[(a+b)(a^2-ab+b^2) \]

  14. UsukiDoll
    • one year ago
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    so we need to write this equation.. what is the cube root of 8 and the cube root of 64?

  15. anonymous
    • one year ago
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    2^3

  16. campbell_st
    • one year ago
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    64 = 4 x 4 x 4 g^3 = g x g x g the problem is the sum of of 2 cubes 8 = 2 x 2 x 2 so the factored form is \[a^3 + b^3 = (a + b)(a^2 -ab + b^2)\]

  17. anonymous
    • one year ago
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    wouldn't it be d

  18. UsukiDoll
    • one year ago
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    and cube root of g^3 ?

  19. UsukiDoll
    • one year ago
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    \[64g^3 + 8 \rightarrow (4g)^3+2^3\] so a = 4g and b = 2 plug this into the sum of cubes equation

  20. anonymous
    • one year ago
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    i did and i got the answer d was i wrong?

  21. UsukiDoll
    • one year ago
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    I don't think so.. I think you're right but just to be sure \[(4g+2)((4g)^2-4g(2)+4)\]

  22. UsukiDoll
    • one year ago
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    \[(4g+2)(16g^2-8g+4)\]

  23. UsukiDoll
    • one year ago
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    yeah it is d

  24. anonymous
    • one year ago
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    okay thank you for the help i have one more to ask about

  25. UsukiDoll
    • one year ago
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    sure

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