- anonymous

(2x – 1)(x + 7) = 0
Did i do this right guessing I distribute
2x*x = 2x^2 + 2x*7=14.
-1* x = x -1*7 = -7
2x^2 +14+ x -7
2x^2 +x = 2x^3
14 -7= 7
2x^3+ 7

- jamiebookeater

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- pooja195

Are we solving for x?

- anonymous

Solve each quadratic equation. Show your work. that's what it says.

- pooja195

so they want the value of x?

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## More answers

- pooja195

(2x – 1)(x + 7) = 0
We would use the 0 product property right? @jim_thompson5910 :/ am i right?

- anonymous

Huh?

- jim_thompson5910

|dw:1437707414800:dw|

- jim_thompson5910

|dw:1437707424790:dw|

- jim_thompson5910

solve each equation for x

- pooja195

i was right :)

- pooja195

@Ashtaroth You are doing more work than needed

- anonymous

More work then needed? What do you mean?

- pooja195

You dont need to do all that work just do what @jim_thompson5910 drew

- anonymous

Oh. Kool then.

- anonymous

So after that i'm finish?

- pooja195

yes u will have 2 solution's

- UsukiDoll

after you solve those equations .. yes.. there should be x = (two numbers)

- pooja195

x=?
x=?

- UsukiDoll

|dw:1437707649100:dw|

- anonymous

2x-1 and x+7=0

- anonymous

Guess i was wrong then :P

- anonymous

I think i got it though. Thank you all for you'r help :)

- pooja195

:)

- UsukiDoll

you were distributing... not solving for x . the problem is already factored

- anonymous

So.. My answer was right or wrong?

- UsukiDoll

your attempt was way off

- pooja195

Wrong you didnt even solve for x

- anonymous

Heh.. So i was wrong?

- pooja195

yes

- anonymous

Okay. so i'm suppose to solve the quadratic equation. then show my work.

- pooja195

|dw:1437708079679:dw|

- pooja195

^solve for x .-.

- jim_thompson5910

focus on just 2x-1 = 0
what number can we replace x with to make the equation true?

- anonymous

-2?

- LynFran

you were suppose to work the problem to solve for x... here is an example|dw:1437715265345:dw|

- jim_thompson5910

2x-1 = 0
2*(-2)-1 = 0 ... replace x with -2
-4 - 1 = 0
-5 = 0 ... this is a false equation so x = -2 isn't the answer

- anonymous

Alright.

- jim_thompson5910

look at what LynFran posted

- UsukiDoll

so we need to find that x that makes the statement true.. @LynFran provided a good example :)

- anonymous

So we divide?

- UsukiDoll

consider
2x-1 = 0
we need to solve for x. ... do we add, subtract, multiply , or divide?

- anonymous

Add?

- UsukiDoll

yeah. add what number to both sides?

- anonymous

2x+1 and -1+1?
3x =0?

- anonymous

Wifi is bad

- UsukiDoll

umm we can't combine 2x +1
however we do add 1 to both sides
2x-1=0
2x=1
now how do we get x by itself

- anonymous

Hmm. subtract -2 from both sides?

- UsukiDoll

no.

- UsukiDoll

hint: use division

- anonymous

divide by 2x/2 1/2?

- UsukiDoll

yeah
2x=1
divide 2 from both sides
2x=1
--- ---
2 2
x = 1/2

- UsukiDoll

now for x+7=0
how do we get x by itself?

- anonymous

add the x with the 7 then divide by 7?

- UsukiDoll

we don't have to do division... for x+7=0 because there is no number attached to the variable
on the previous problem we had to divide because we want x by itself
we just have x+7=0

- UsukiDoll

what's the opposite of addition?

- anonymous

subtraction.

- UsukiDoll

yes. just subtract 7 from both sides

- anonymous

7/7 7/0 =7

- UsukiDoll

whoa we can't have 7/0 that's undefinded

- anonymous

Okay.

- UsukiDoll

x+ 7 = 0
-7 -7
x+7-7 =0-7
what is 7-7
what's 0-7

- anonymous

-7?

- UsukiDoll

woohoo!

- UsukiDoll

so our two solutions are
x= -7 and x =1/2

- anonymous

Alright do we plug them in or our we finish?

- UsukiDoll

we're done

- anonymous

Thanks XD I am tired. Good night

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