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Are we solving for x?
Solve each quadratic equation. Show your work. that's what it says.
so they want the value of x?
solve each equation for x
i was right :)
More work then needed? What do you mean?
Oh. Kool then.
So after that i'm finish?
yes u will have 2 solution's
after you solve those equations .. yes.. there should be x = (two numbers)
2x-1 and x+7=0
Guess i was wrong then :P
I think i got it though. Thank you all for you'r help :)
you were distributing... not solving for x . the problem is already factored
So.. My answer was right or wrong?
your attempt was way off
Wrong you didnt even solve for x
Heh.. So i was wrong?
Okay. so i'm suppose to solve the quadratic equation. then show my work.
^solve for x .-.
focus on just 2x-1 = 0 what number can we replace x with to make the equation true?
you were suppose to work the problem to solve for x... here is an example|dw:1437715265345:dw|
2x-1 = 0 2*(-2)-1 = 0 ... replace x with -2 -4 - 1 = 0 -5 = 0 ... this is a false equation so x = -2 isn't the answer
look at what LynFran posted
So we divide?
consider 2x-1 = 0 we need to solve for x. ... do we add, subtract, multiply , or divide?
yeah. add what number to both sides?
2x+1 and -1+1? 3x =0?
Wifi is bad
umm we can't combine 2x +1 however we do add 1 to both sides 2x-1=0 2x=1 now how do we get x by itself
Hmm. subtract -2 from both sides?
hint: use division
divide by 2x/2 1/2?
yeah 2x=1 divide 2 from both sides 2x=1 --- --- 2 2 x = 1/2
now for x+7=0 how do we get x by itself?
add the x with the 7 then divide by 7?
we don't have to do division... for x+7=0 because there is no number attached to the variable on the previous problem we had to divide because we want x by itself we just have x+7=0
what's the opposite of addition?
yes. just subtract 7 from both sides
7/7 7/0 =7
whoa we can't have 7/0 that's undefinded
x+ 7 = 0 -7 -7 x+7-7 =0-7 what is 7-7 what's 0-7
so our two solutions are x= -7 and x =1/2
Alright do we plug them in or our we finish?
Thanks XD I am tired. Good night