Please help fast I've been trying to complete this for an hour and I need to get it done before 6am
The function f(t) = t2 + 4t − 14 represents a parabola.
Part A: Rewrite the function in vertex form by completing the square. Show your work. (6 points)
Part B: Determine the vertex and indicate whether it is a maximum or a minimum on the graph. How do you know? (2 points)
Part C: Determine the axis of symmetry for f(t). (2 points)

- anonymous

- jamiebookeater

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- triciaal

vertex form a(x-h)^2 + k
h = -b/2a from standard form ax^2 + bx + c
k = f(h)
vertex (h, k)

- anonymous

is that A?

- triciaal

axis of symmetry is the line x = h

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## More answers

- anonymous

Would this be a maximum because I don't see any negatives?

- triciaal

|dw:1437713419800:dw|

- triciaal

stat with your given equation what is a, b c ?

- anonymous

oh so the vertex is a minimum then

- triciaal

start

- triciaal

next what is -b/(2a)

- triciaal

is everything clear now?

- anonymous

i dont understand what you mean by what is -b/(2a) but ive been attempting to teach myself how to do these problems for an hour and at this point i dont think im capable of learning it without a physical teacher but so far for this question my answers are,
"PART A:
vertex form a(x-h)^2 + k
h = -b/2a from standard form ax^2 + bx + c
k = f(h)
vertex (h, k)
PART B:
it is a minimum on the graph because it is the lowest point of the parabola at (-2,-18)
PART C:
axis of symmetry is the line x = h "

- triciaal

you need to put the number
that was a whole lot for not responding to me helping you

- anonymous

Put the number in where and im sorry if i wasn't responding this stuff really confuses me

- triciaal

|dw:1437714409139:dw|

- triciaal

|dw:1437714492874:dw|

- triciaal

|dw:1437714526200:dw|

- anonymous

put in 4 and 1?

- anonymous

For A and B

- triciaal

whenever you don't understand something it is ok to ask for more clarification

- triciaal

correct

- triciaal

now do you see why h = -2?

- anonymous

ok so i have -4 on the top and 2 on the bottom silpfy and i get h=-2 is that right?

- anonymous

simplify*

- triciaal

to complete the square you are adding what is necessary to your original equation to make it a perfect square and keep the balance of the equation

- anonymous

is h=-2 the vertex?

- triciaal

|dw:1437714802686:dw|

- anonymous

and how do you know whats necessary to add to the original equation and how do i know when its a perfect square

- triciaal

h is the x-coordinate of the vertex
the vertex is a point (h, k)

- anonymous

the topmost part in your drawing is the original equation right?

- triciaal

the vertex is the maximum or minimum point of the parabola

- anonymous

i know what the vertex is but like its confusing that vertex point is letters

- triciaal

|dw:1437715112937:dw|

- triciaal

vertex is a point (h, k) just like (x, y)

- anonymous

are we going to find the numbers that are the point though and if so how do we find them

- triciaal

you need to stop making things complicated

- triciaal

stop and actually read my responses

- anonymous

im sorry learning math is very hard for me i am reading your responses its just hard for me to process all this information

- triciaal

now, do you understand what a perfect square is?

- anonymous

i dont understand it too much

- triciaal

it is very hard because you are not being open clear you mind so you can make room to understand the responses

- triciaal

|dw:1437715452917:dw|

- triciaal

an entity multiplied by itself will give a perfect square

- anonymous

no its like im sorry but its the way i think im trying and im listening i promise

- triciaal

|dw:1437715523167:dw|

- anonymous

|dw:1437715469206:dw|

- triciaal

|dw:1437715610791:dw|

- anonymous

why is the second t bottom row squared is it still perfect?

- anonymous

oh
wait i see what you did you did FOIL

- triciaal

|dw:1437715712439:dw|

- triciaal

|dw:1437715836314:dw|

- anonymous

so image before you used FOIL then simplify then in the next one you did the zeros thing?

- anonymous

also where did -4 come from

- triciaal

to make a perfect square you had to add 4 so to keep the balance of the equation you -4

- triciaal

look at the drawing in blue given

- anonymous

what does given mean?

- triciaal

|dw:1437716009964:dw|

- triciaal

what you were given in the question to start with

- anonymous

yeah i remember that image is it working bottom to top?

- triciaal

the question gave you the part originally marked in blue.
to make a perfect square you added 4
to keep the balance of the equation you -4.
+4 added to -4 = 0 so you are not changing the original just expressing it differently

- triciaal

|dw:1437716216823:dw|

- anonymous

oh i think i get it im still confused to how all of this applies to my original question though :( could you explain?
is it a part of part A B or C?

- triciaal

read the question slowly then look at the response

- anonymous

My three questions the a b and c?

- triciaal

Part A: Rewrite the function in vertex form by completing the square. Show your work. (6 points)

- anonymous

So i think we are on- yeah question a
because we are completing the square

- triciaal

Part B: Determine the vertex and indicate whether it is a maximum or a minimum on the graph. How do you know? (2 points)
vertex (h, k)
look at the vertex form of the equation you just wrote in A after completing the square

- triciaal

when a is positive the parabola opens up
the vertex is at the minimum
as you see in the sketch

- anonymous

part b it is a minimum

- anonymous

i know from that picture you showed me

- anonymous

so what you just said is the answer to B

- anonymous

and is (-2,-18) the vertex in 1

- triciaal

but you see why I had that point h = -2 and k = -18
Part C: Determine the axis of symmetry for f(t). (2 points)
the axis of symmetry is the line that will "cut the parabola in half where the vertex is"

- anonymous

i mean A not 1

- anonymous

(-2,-18) is a point on the axis of symmetry?

- anonymous

since it is the vertex?

- anonymous

we need to cut it in half down y axis?

- triciaal

|dw:1437717207003:dw|

- anonymous

yeah i get that how do we convert that into text though?

- triciaal

i dont understand what you mean by what is -b/(2a) but ive been attempting to teach myself how to do these problems for an hour and at this point i dont think im capable of learning it without a physical teacher but so far for this question my answers are,
"PART A:
vertex form a(x-h)^2 + k
h = -b/2a from standard form ax^2 + bx + c
k = f(h)
vertex (h, k)
PART B:
it is a minimum on the graph because it is the lowest point of the parabola at (-2,-18)
PART C:
axis of symmetry is the line x = h " what is h?

- triciaal

PART C:
axis of symmetry is the line x = h " what is h?

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