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Rolling an even number with a die and rolling an odd number with a die.
go back to the theory of probability
mutually exclusive if there is a disjoint between two events
let me provide an example
Mutually exclusive If you roll an even number, it is not odd ,and if you roll an odd number it is not even. Inclusive would be: roll a 3 or an odd number. Since 3 is odd, rolling a 3 or an odd number are not mutually exclusive events.
the same concept applies in every event.
so the two dies are designed to only give you odd or even respectively?
the die is a poor example to drive the concept home if you're learning a mutually exclusive events.
Mutually exclusive events are events that cannot happen at the same. For example, a mutually exclusive event would flipping a coin and seeing if you get H or T. The formula to solve mutually exclusive probability is f(H)+f(H). Mutually inclusive events are events that can happen at the same time. For example, mutually inclusive events include rolling dice, to see if you get even or odd. The formula to solve mutually inclusive probability is d(e)+d(o)-d(e and o). Would this be a good answer?
there you have it.
you must be able to provide an intersection of two sets (events) to be able to cite that they are inclusive. if no intersection occurs, which is null, then we say they are mutually exclusive or disjoint.
Okay (to make sure I have it), If I roll 2 dice of 6 sides, the probability of getting odd, inclusive. The equations would be P(A) for even and P(A1) would be odd.
no. you just say P(A) because A' is 1-P(A) or what is not P(A)