anonymous
  • anonymous
The expression to find the perimeter of a rectangle is 2(length + width). What is the perimeter, in units, of a rectangle of length fraction 1 over 7 unit and width fraction 1 over 2 unit? fraction 1 and 1 over 7 units fraction 1 and 2 over 7 units fraction 4 over 9 unit fraction 2 over 9 unit
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
anonymous
  • anonymous
phi
  • phi
length is 1/7 width is 1/2 can you add those two fractions?

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phi
  • phi
\[ \frac{1}{7}+ \frac{1}{2} \] use 14 as the common denominator
UsukiDoll
  • UsukiDoll
Perimeter = 2L + 2W let l = 1/7 and w = 1/2 Perimeter =\[2(\frac{1}{7})+2(\frac{1}{2})\]
anonymous
  • anonymous
ya
UsukiDoll
  • UsukiDoll
ok then multiply first.
anonymous
  • anonymous
multiply what
UsukiDoll
  • UsukiDoll
2 x 1/7 + 2 x 1/2
UsukiDoll
  • UsukiDoll
what is 2 x 1/7 what is 2 x 1/2
UsukiDoll
  • UsukiDoll
|dw:1437738157402:dw|
anonymous
  • anonymous
0.285714285714
anonymous
  • anonymous
for the first one
anonymous
  • anonymous
2 x 1 over 2 is 1
UsukiDoll
  • UsukiDoll
ok... tip: keep your result in fraction form because decimals are nasty
anonymous
  • anonymous
i used calculator
UsukiDoll
  • UsukiDoll
|dw:1437738291917:dw|
UsukiDoll
  • UsukiDoll
not a good idea to use calculator... I know universities that ban them .
UsukiDoll
  • UsukiDoll
anyway we take the LCD because we have one fraction and one whole number
UsukiDoll
  • UsukiDoll
|dw:1437738349274:dw|
anonymous
  • anonymous
yes
UsukiDoll
  • UsukiDoll
so it's just what's 2 +7 you'll get the numerator
anonymous
  • anonymous
9
UsukiDoll
  • UsukiDoll
yeah so the perimeter is 9/7
anonymous
  • anonymous
\[4\over9\]
anonymous
  • anonymous
for the firdt one
anonymous
  • anonymous
first
UsukiDoll
  • UsukiDoll
what is this?
UsukiDoll
  • UsukiDoll
oh ... I see your choices are in mixed fraction form . we just have to adjust 9/7 because it's improper
anonymous
  • anonymous
yup
UsukiDoll
  • UsukiDoll
|dw:1437738535938:dw|
UsukiDoll
  • UsukiDoll
though both versions are right XD
anonymous
  • anonymous
there is one more
UsukiDoll
  • UsukiDoll
open a new question XD

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