anonymous
  • anonymous
Help with adding square roots
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
\[2\sqrt{k}+\sqrt{k}-3\sqrt{k}\]
idku
  • idku
if you had \( \tt 2x+x-3x\) then what would you get?
anonymous
  • anonymous
just x right?

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anonymous
  • anonymous
-x
idku
  • idku
2 + 1 - 3 = 0
anonymous
  • anonymous
yeah then 0
idku
  • idku
2x + x - 3x = 0
idku
  • idku
So then, \(\tt 2\sqrt{k}+\sqrt{k}-3\sqrt{k}=0?\)
idku
  • idku
is that correct?
anonymous
  • anonymous
looks like it idk answer choices are a.) 0 b.) -sqrt k c.) sqrt 3k
idku
  • idku
ok, so we have agreed upon the fact that: \(\tt 2+1-3=0\) And same way, \(\tt 2a+a-3a~~\longrightarrow~~2a+1a-3a=0\) Now, \(\tt 2\sqrt{k}+\sqrt{k}-\sqrt{k}a~~\longrightarrow~~2\sqrt{k}-1\sqrt{k}-3\sqrt{k}=?\)
anonymous
  • anonymous
0
idku
  • idku
Yes, that is the correct answer.

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