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A circular picture is 8 inches in diameter. Part A What is the area of the picture in square inches? A. 4π square inches B. 8π square inches C. 16π square inches D. 32π square inches Part B A frame that is 2 inches wide surrounds the picture. What is the total area of the picture and the frame in square inches? A. 4π square inches B. 12π square inches C. 36π square inches D. 40π square inches
\[A = \pi r^2\]
I don't get it.......
oh the answer is in pi so 42 pi is your answer
what don't you get?
But 42 is not in the answers...
or 16 pi sry
Part A = pi r^2 = pi 4^2
as 4 is the radius
idk why I wrote 42 xD
Part B the radius increases by 2 so area = pi * 6^2
@Chumpian How did you get that?
\[A = \pi r^2\] so 4 is the radius (r) and what's 4 squared?
yep and they want the answer in terms of pi so 16pi is your answer
Now i need part B
So again you use the equation \[A = \pi r^2\]
They said they added two inches to the frame
so the radius is now 6
So what do you do next?
area = pi r^2 where r = radius r is now 6 so its pi * 6^2 = 36 pi
Well I was gonna let her do that but thx xD
Ok sry what is going on?
ok so the radius for part B is 6
We are doing the same thing as we did in part A
so what do we do with the radius that equals 6
\[A = \pi r^2\]
Ok but that is A
but we are doing the same thing as Part A but just with a larger radius
So when we plug in the 6 \[A = \pi 6^2\]
What do you do with the 6?
multiply is by itself so 12
that would be 6 x 2 = 12 but squaring a number would be 6 x 6 = 36
Oh yea sorry
so then 36?
yep and they want it in terms of pi So your answer is?